Split_00079 - 9.62 Basis : 1 mol CO burned. 1 mol CO n 0...

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9- 79 9.62 a. b. Basis : 1 mol CO burned. CO O CO 1 2 22 +→ , Δ ± . H c o kJ mol =− 282 99 ( – 0.5) n 1 mol CO 0 mol O 2 3.76 n 0 mol N 2 25°C n 1 mol CO 0 mol O 2 3.76 n 0 mol N 2 1400°C 2 Oxygen in product gas : nn n 10 0 05 = mol O fed 1 mol CO react 0.5 mol O 1 mol CO 2 2 bg . References : CO, CO , O , N at 25 C 222 D Substance mol kJ mol mol kJ mol CO O N3 CO in in out out 1 23 n H n H H H H ±± . ± .. ± ± 00 5 76 0 376 1 20 0 −− O g,1400 C : C kJ mol N g,1400 C : C kJ mol CO g,1400 C : C kJ mol 2O 2N 2C O 2 Table B.8 2 Table B.8 2 Table B.8 °= = = = B B B () . . (). HH 1 2 3 1400 47 07 1400 44 51 1400 7189 D D D E.B.: ΔΔ Hn H n H n H n n CO c i i i i =+ −= +− + + = ± . . o out in 282 99 47 07 0 5 44 51 3 76 7189 0 bgb g ⇒= n 0 1094 m o l O 2 Theoretical O mol CO mol O mol CO mol O == 1 0500 b g Excess oxygen: 1094 100% 119% mol fed mol reqd. 0.500 mol excess oxygen ×= Increase %XS air T ad would decrease , since the heat liberated by combustion would go into heating a larger quantity of gas (i.e., the additional N
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