Split_00081 - 9.64 C 3 H 6 O g + 4O 2 g 3CO 2 g + 3H 2 O l...

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9- 81 9.64 a. b. C H O g 4O g 3CO g 3H O l , kJ mol 36 2 2 2 o bg a f +→ + = Δ ± .4 H i 1821 Basis : 1410 m STP feed gas 10 mol 1 min 22.4 m STP 60 s mol s feed gas 33 3 min = 1049 Stochiometric proportion: 1 mol C H O 4 mol O 4 3.76 15.04 mol N mol 2 2 ⇒⇒ × = + + = 1 4 1504 20 04 .. y CHO 1 mol C H O 20.04 mol mol C H O mol == 0 0499 . , y O2 2 4 20.04 mol O mol 0 1996 . Feed gas 1049 mol/s O 0.7505 N 2 T (°C), 150 mm Hg f Rel. satn = 12.2% Preheat Q (kW) 1 Feed gas 562°C Reaction Product gas n 1 (mol CO /s) 2 n 2 (mol H O/s) 2 n 3 (mol N /s) 2 T (°C) a Cooling Product gas 350°C Q (kW) 2 Relative saturation mm Hg 0.122 mm Hg C Table B.4 o =⇒ = ⇒= = = 12 2% 0122 0 0499 1500 61352 50 0 . yP p T pT f f di b g Feed contains 1049 mol s 0.0499 C H O mol mol C H O s b g = 52 34 . 1049 0.1996 mol O s 2 b g = 209 4 . 1049 0.7505 mol N s 2 b g = 787 3 . Product contains n n n 1 2 3 52 34 3 157 0 52 34 3 157 0 787 3 14 25 14 25% H 71.5% N = U V | W | . . . b g b g mol CO s mol H O s mol N s mole% CO O 2 2 2 2 2 2 References :
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This note was uploaded on 01/07/2012 for the course CH E 210H at Pennsylvania State University, University Park.

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