Split_00093 - 9.69(cont'd Hi = T 0 C dT H i pi kJ mol 25 kJ molC z n H i i =-1575 10 6 kJ h =-9.888 10 6 kJ h in n H i out i LM5595dC i 1261dC i

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9- 93 ± ± H H Cd T i i pi T =+ ⋅° z kJ mol kJ mol C Δ 0 25 ² ± . nH ii in kJ h =− × 1575 10 6 ² ± . C C C CC d T T p p p T pp v p s T ad out CH N C H HC O C O H O 3 C 3 kJ h kJ 10 J kJ 423 2 out 22 2 z z × + + + L N M ++++ O Q P + 9 888 10 5595 1261 7931 52816 23311 3458 3013 1 1 6 25 298 273 di bg We will apply the heat capacity formulas of Table B.2, recognizing that we will probably push at least some of them above their upper temperature limits ² ± .. . . . T T dT T T dT T T ad ad out kJ h z z × + + × × ++ × F H G I K J −− + 9 888 10 3902 12185 59885 10 10162 10 32 411 0 031744 14179 10 64 2 7 3 25 6 2 298 273 ej ² ± . . . T T T T T a a a a a out × + + × × + × + 1000 10 3943 0 6251
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This note was uploaded on 01/07/2012 for the course CH E 210H at Pennsylvania State University, University Park.

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