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Split_00002

# Split_00002 - 8.3(cont'd b C p = Cv R C p kJ(mol o C...

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8- 2 8.3 (cont’d) b. C C R p v = + C T T T T p [ ] ( . . . ) . . . . kJ / (mol C) o = + × × + = + × × 0 0252 1547 10 3012 10 0 008314 0 0335 1547 10 3012 10 5 9 2 5 9 2 Q H n C dT T T dT P T T = = = + × × = × z z Δ 1 2 0 245 0 0335 1547 10 3012 10 9 65 5 9 2 25 1000 mol [kJ / (mol C)] 10 J Piston moves upward (gas expands). o 3 ( . ) [ . . . ] . c. The difference is the work done on the piston by the gas in the constant pressure process. 8.4 a. ( ) ( ) ( ) ( ) 6 6 o 5 C H 40 C 0.1265 23.4 10 40 0.1360 [kJ/(mol K)] p l C = + × = b. C p v d i b g b g b g b g b g C H o 6 6 C [kJ / (mol C) 40 0 07406 32 95 10 40 2520 10 40 77 57 10 40 0 08684 5 8 2 12 3 ° = + × × + × = . . . . . ] c. C p s d i b g b g b g b g C 313 K 0.009615 kJ / (mol K)] = + × × = 0 01118 1095 10 313 4 891 10 313 5 2 2 . . . [ d. Δ ± . . . . . H T T T T v C H 6 6 3 kJ mol b g = + × × + × O Q P P = 007406 32 95 10 2 2520 10 7757 10 4 3171 5 2 8 3 12 4 40 300 e. Δ ± . . . . H T T T C s b g = + × + × O Q P P = 0 01118 1095 10 2 4 891 10 3459 5 2 2 1 313 573 kJ / mol 8.5 H O (v, 100 C, 1 atm) H O (v, 350 C, 100 bar) 2 o 2 o a. ± H = = 2926 2676 250 kJ kg kJ kg kJ kg b. ± . . . . . H T T T dT = + × + × × = z 0 03346 0 6886 10 0 7604 10 3593 10 8845 5 8 2 12 3 100 350 kJ mol 491.4 kJ kg Difference results from assumption in (b) that ± H is independent of P . The numerical difference is Δ ± H for H O v, 350
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