Split_00003 - 8.7 1 b g 18 T b Fg - 32 = 0.5556T b Fg -...

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8- 3 8.7 TT T °= °− = °− CF F bg 1 18 32 05556 17 78 . .. CT T p cal mol C F F ⋅° = + = + ′ ° b g b g 6890 0 001436 05556 17 78 6864 0 0007978 . ... ⋅° = ° ⋅° ° = E CC C pp p Btu lb - mole F cal 453.6 mol 1 Btu 1 C mol C 1 lb - mole 252 cal 1.8 F drop primes b g 100 . p Btu lb - mole F F ⋅° = + ° b g 6864 0 0007978 8.8 T T p di CH CH OH(l) o 32 100 [kJ / (mol C)] =+ 01031 01588 01031 01031 0 000557 . QH T T == + F H G O Q P × Δ 550 789 01031 0 000557 2 2 20 78 5 . . . . L s g 1 L 1 mol 46.07 g = 941.9 7.636 kJ / s = 7193 kW kJ mol ±² ³³³³ ³´ ³³³³³ 8.9 a. µµ ,. . , T T T d T + × × + × = −− z Δ 5 000 0 03360 1367 10 1607 10 6 473 10 17 650 58 2 1 2 3 100 200 mol s kW kJ mol ¶· ³³³³³³³³³³³³ ³¸ ³³³³³³³³³³³³³ b. QUHP VH n R T ==− =− = ⋅⋅ = ΔΔ Δ Δ Δ 17 650 50 13 490 ] , kJ kmol 8.314 [kJ / (kmol K) 100 K kJ b g b g The difference is the flow work done on the gas in the continuous system. c. Q additional = heat needed to raise temperature of vessel wall + heat that escapes from wall to
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