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Split_00013

# Split_00013 - 8.31 520 kg NH 3 103 g 1 mol 1h Basis = 8.48...

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8- 13 8.31 3 3 3 520 kg NH 10 g 1 mol 1 h Basis: 8.48 mol NH s h 1 kg 17.03 g 3600 s = 8.48 mol NH /s 3 n 1 25°C (mol air/s) T °C n 2 (mol/s) 0.100 NH 0.900 air 600°C 3 Q = –7 kW NH balance: mol s 3 848 0100 848 22 .. . =⇒ = nn Air balance: mol air s 1 n == 0900 848 763 . bg b g References for enthalphy calculations: NH g 3 , air at 25 ° C NH kJ mol 3i n out NH Table B.2 from out 3 ± . ±± . H HC d T H p C p = = z 00 2562 25 600 di Air: () 58 2 1 2 3 J mol C 0.02894 0.4147 10 0.3191 10 1.965 10 p CT T T −−− ⋅° = + × + × × in 25 12 4 8 3 5 2 ˆ 0.4913 10 0.1064 10 0.20735 10 0.02894 0.7248 kJ mol T p d T TT T T −− = =− × + × + × + 600 out 25 ˆ 17.55 kJ mol p d T Energy balance: out in ˆˆ ii Q H nH =Δ = ∑∑ ( ) ( ) ( ) ( )( ) 3 12 4 8 3 5 2 7 kJ s 8.48 mols NH s 25.62 kJ mol 76.3 mols air s 17.55 kJ mol 8.48 0.0 76.3 0.4913 10 0.1064 10 0.20735 10 0.02894 0.7248 T T −= + × +×+ ×+ Solve for
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