Split_00022 - 8.47 Basis 226 m 3 min 273 K 10 3 mol 309 K...

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8- 22 8.47 Basis: 226 m K 10 mol min K 22 m STP mol humid air min 3 3 3 273 309 415 8908 . b g = . DA = Dry air ± ( Q kJ / min) 8908 mol 0 0 / min mol H O(v) / mol] (1- (mol DA / mol) 36 C, 1 atm, 98% rel. hum. 2 o y y [ ) ± ( [ ) n y y 1 1 1 mol / min) mol H O(v) / mol] (1- (mol DA / mol) 10 C, 1 atm, saturated 2 o ± [ n 2 mol H O(l) / min], 10 C 2 o a. Degree of freedom analysis : 5 unknowns – (1 relative humidity + 2 material balances + 1 saturation condition at outlet + 1 energy balance) = 0 degrees of freedom. b. Inlet air: y P p y w 0 0 0 98 36 0 98 44 563 0 0575 = ° = = B . . ( . . * C mm Hg) 760 mm Hg mol H O(v) mol Table B.3 2 b g Outlet air: y p P 1 10 9 760 mm Hg 0 0121 = = = ( . o 2 C) / .209 mm Hg mol H O(v) mol b g b g Air balance: 1 0 0575 1 0 0121 8499 1 1 = = . (8908 . ± ± b g b g mol / min) mol / min n n H O balance: 0.0575 mol min
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