Split_00023 - 8.48 Basis: 746.7 m 3 outlet gas / h 3 atm 1...

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8- 23 8.48 Basis: 746.7 m outlet gas / h atm 1 kmol 1 atm 22.4 m STP kmol / h 3 3 3 100 0 bg = . Antoine: () ( ) 1175.817 log 6.88555 0 C 45.24 mm Hg, 75 C 920.44 mm Hg 224.867 vv v pp p T ∗∗ = °= + y p P v out 6 14 C kmol C H kmol = ° == 0 4524 3760 0 0198 . . , y p P v in 61 4 C kmol C H kmol = ° 0 90 75 0 90 920 44 0 363 .. . . b g b g N balance: kmol h 2 ± ± . nn 11 1 0 363 100 1 0 0198 1539 −= = b g C H balance: kmol C H h 4 4 1539 0 363 100 0 0198 5389 22 . ±± . b g b g b g =+ = l Percent Condensation: 5389 0 363 1539 100% 965% . . kmol h condense kmol h in feed b g b g ×× = References : N 2 (25 o C), n -C 6 H 14 (l, 0 o C) Substance N i n m o l h -C H in kJ mol in in out out 2 4 4 nH n H n nr H nl ²² ± ² . 98000 146 98000 0 726 55800 44 75 2000 3333 53800 0 0 −− N: CH ( v ) : 26 1 4 ² , . . . H C T n H C dT H C dT v p v T =−
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This note was uploaded on 01/07/2012 for the course CH E 210 at Penn State.

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