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Unformatted text preview: C H 3 N + H COO- R C H 2 N Form IV = lose H from amine Form III = lose H from R group H 3 N + Form II = lose H from carboxyl group Form I = fully protonated No H lost (fully protonated) 0.5 1 1.5 2 OH-Equivalents pH pK 1 pK 2 pK R 2 4 6 8 10 12 Tyrosine Cysteine Aspartate Glutamate Histidine Lysine Arginine [I] = [II] [II] = [III] [III] = [IV] H lost from R group H lost from carboxyl group H lost from carboxyl, amino, and R group (fully deprotonated)...
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This note was uploaded on 01/07/2012 for the course PHCH 51311 taught by Professor Nightingale during the Summer '11 term at Palmer Chiropractic.
- Summer '11