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Unformatted text preview: Dr. Gundersen Phy 205DJ Test 1 15 February 2010 Signature: Name: 1 2 3 4 5 Idnumber: Do only four out of the five problems. The first problem consists of five multiple choice questions. If you do more only your FIRST four answered problems will be graded. Clearly cross out the page and the numbered box of the problem omitted. Do not write in the other boxes. TO GET PARTIAL CREDIT IN PROBLEMS 2 - 5 YOU MUST SHOW GOOD WORK. CHECK DISCUSSION SECTION ATTENDED: [ ] Dr. Gundersen 2O, 9:30 - 10:20 a.m. [ ] Dr. Nepomechie 2P, 11:00 - 11:50a.m. [ ] Dr. Alvarez 2Q, 12:30 - 1:20 p.m. [ ] Dr. Barnes 2R, 2:00 - 2:50 p.m. [ ] Mr. Perez-Veitia 2S, 3:30 - 4:20 p.m. Vector relations: vector a = a x i + a y j , a = | vector a | = radicalBig a 2 x + a 2 y , = tan- 1 a y a x , a x = a cos , a y = a sin vector b = b x i + b y j + b z k , b = | vector b | = radicalBig b 2 x + b 2 y + b 2 z , b = vector b /b, vector v AC = vector v AB + vector v BC For constant acceleration: v = v + at, x = x + v t + 1 2 at 2 , v 2 = v 2 +2 a ( x- x ) , x = x + 1 2 ( v + v ) t, x = x + vt- 1 2 at 2 v av = 1 2 ( v + v ) = v + 1 2 at 2 , vector r ( t ) = vector r + vector v t + 1 2 vector a t 2 , vector v ( t ) = vector v + vector a t For nonconstant acceleration: vector v = dvector r dt , vector v av = vector r 1- vector r t 1- t , x 1- x = integraldisplay t 1 t v x ( t ) dt vector a = dvector v dt , vector a av = vector v 1- vector v t 1- t , v x 1- v x = integraldisplay t 1 t a x ( t ) dt Physics 205DJ TEST 1 15 September 2010 Dr. Gundersen Phy 205DJ Test 1 15 February 2010 [1.] This problem has five multiple choice questions. Circle the best answers....
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