SP07hwk1soln

SP07hwk1soln - i Hemmer-1.: 14:1 g ME 5361 ' % gyms mm ; ®...

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Unformatted text preview: i Hemmer-1.: 14:1 g ME 5361 ' % gyms mm ; ® “wwmw WWWWWWW_WWWWWWWWWWW WW“ “W‘TWWMWM Pr$bl€zm . , ‘ Gm: Vfiiouufih ooho‘kH‘COM' Pa? O NPOL‘ : : 623,23. =100 13+“: 6.9mm .. . i am; @ 0" "3) l .. I . ; ® To , . \ . . ' § © F (N) ’ I ' . I ' .. .. E. _ . . ; ® 62 (MN) hue-“4% k6 , Thi— aOK ' i _ 3 .53" 0* I ' 1: @ Is :3 9.51;..— _ . i 0* ‘.-‘ when-e, GS =5 3515. 5mm Fa? C3 _ _ C25 ' _ ' . ° " Com Mffirminfifigfwm one; §C+w2© was/5;. ®c%\2‘l%ofihuck CDfiWI'Q-emfi' Takes QM“ my mm. “519+; New?” 05 «1.357% _ _ Fe. ' . 3" _ _ _ i In Sicily-e23"? N “Fwéam 71 o ibAmrm¥® ' ' CD 0&0erth 08:33 I‘Eér'mHv-QJ §fi+ OCR; I E a. +(75—12nefj “WW-5} 2m ' I 1'. ‘ ' I aafihafi an gp¥9~+§ 435% l .. Ha Hemmer-k “filmed? AAE 5:361 gyms who? t 7 r .‘Hwn mm“: cmbflofifi: \ if; . , 21:3 a “*W‘.‘ -P. 754/35 r . 656“ 317%?) 0 $3 ) +93% ' 1 <w><a=a $2) mm .. ' Qaa‘zm‘) ' c"= HH {H E11 @ mfl:f“‘/&<§“9 Km) \‘3 Tc, ‘=_ (0*)? (Efl)"@+D/@‘9 .' S - . —(i.5'+\)/(n;3: . I. I :TQ: <4WO%§‘>}’<L5)CJOIE%> {lg—1) : ._ .. (mwggm) \ a .(fiwflvfl : 30960th iamfl (NWV-gf .. _ 1 Hofiegerkfiwcmfi ME 53$ g Siam?) 2.0m ' i6? ' WWWWWWWWW WWWWW WWWWWWWWW} WWW i Prablem.%1(mn® . g F " 00° FcA+ ... x . .LQSPQ ’W). M j 1: 4.337%}34071mefi 'T-g; _ [Hr \9'3‘7‘5‘9 F = agelebé N 3 I i i . @ «mer I Aswme; : LH; (D "‘D] F:le T I” ___.....,9l - “0 WW}; afimu‘hbn ‘ ' ' . (:5 m‘rszam mmziw‘wfi ; i f .. fisn;5ffi‘am.. _ _ ® .heakd {afierfirial energy): Khefifumeray (\Jfivg'O‘) ' ' ®I H; mi‘hs‘ as Peflafi' 5M_Ji€n+ers ad“ badih-Sftamwrfi Wm, .' Vtgg: \ZQfl‘Wn +0 § Hit? 1%“ mgw However—k fliflfiifiiW\WEWEPIJEWEEZWQWGBW g mum # :1. (Gang 3 @ (can‘t) E i i i - fin -- 40236; W: Fm = 1+ O .3 “3/5, 9 ,f k N + 59: . C) = {3,03 giwg 35% 67.1 ksk (met - M3 :2] ' ., ' 192fo , L33 LEM * = g i i “FEES? “WWWWWWWWMMW iHommorkiflcwnf): AAE S‘Zfi - ijjimigglmimgm E . . i and. PW Cg vs mean-awn wkszfi Pgapm' ' jiacmewk mm.) ME 55%! WMWMW“WWW\WMM“WM m“ f“ in #7? H3 '55" A WW «:3 $9 I 353‘" V (1‘ ' 4) __1; "3/6. “3/1 Ni 1 Jigqg flng ’7. __ -Fc. “7 ‘C'éa fill J‘s—t “ilk/Fe, I ' 6;;— Ka< ~'_'_ : 27 _ I fr 0; Maxzrém w m'l'nfmcu dCfi/aiPe/FQ" G 50'. . . 0‘27: iii) Ki <%>“f07-:(a + ka(£&>—Y1§qn/ai I R? EE “gi‘XWfiW/fifl‘v’“ E. _V_L. :75 ‘_ Homework #1 (mm-j AAE 5561 Swag 9.097 3 E ' . dmduha 337 Kg I 56" Kl 0'“ 'K; a. iQ-yD/(fifl . ._ I E; ' *6-1 (6+1 _ I W = <1+| ' :1 k; NON 0‘ "JG-X- 1-1:! bub To PC Fr; .—. Lfgbfia' —- 01%) FL I _ . “‘50 $3 ! Homavoerl: #ijnt) AAE ‘53“! ' Prablem fiMWhD I defi-lééfiya‘ +0 fibre: mm. gavkerf Q) ' (1:1)}: fig)‘<6"9/s_ '1” ,4 =- O 95 (PG- 0'" Fa _ w ... .... mo ) Pa ‘6 " ‘6"l 'Vor Q if». = + K ) Po 3‘ .FM. 75:“). m = 0,56% :kl‘oh LOFPQJSPQfidS F6 I O M6519?" efilfl - bbvneds‘j Wis camo+ 'bc a vodick- exfmsxem whaifif‘) +m~$aw C5 :5 mmtwmdx whet} ® I‘% ‘50 ‘or 5%“: Pg, Hamawerk. 111.1 ME 33‘! Syn-Q 3‘00 l WWW WWWMMWW‘.WWW‘MJMWW‘MNWWmmmmwummm‘_‘__.m_.___m___“m‘_mmm_mmm wmmmrwwm‘WMW. a Prob lgzmfié ‘ 6&2 make cow’rwr (F W» 2-) 0mm.) 1 Po *3 9&5?) Fs‘! Tag éqwsR 5 “La ’1“;qu I m: M} PiQfiAT vs. 2 agiumxfis l-D mafium New E 6050; ._.—-5 Pro maker-e : 3 (Eran !“ W32. can oodoviarl'aa arosxi‘wsegofio .l ) «majA J vs. 2 - wn‘fovf‘ PVOHEA 0h Pmatn® ii F MK Ioczofi‘ h a? ‘mimom r (ear A - 44114 16‘ ‘HQ. i ) “Ahmad ragius , rr:<or +hroa+ (32% {A4,}. E i i i i i 2 § 1 2 E - é r+ = 0.500 1n (mm: 86) As m: = 0.7354 ma A a) i 319 Gabon-Xe; ama rfiwcfikfi)‘ 1%, asdcuw’nm a owed \o 0 WHO“ , 2. ' Use; M + ‘6 Ha +0 +2: 4;:- \ son-L N) 4%).» High tin—A m $33112; béugfimfsfpo mm SH" boéedw NEG; '~ _ v _ a ‘31.!!! f5“ AR(2.)-= £22: .J. @393 a“ r) I. J -+ _- 23.7-14qu r F[M(Z)IAE(Z)]= [- W> J . >— AR(2.> _ ,+ .P‘egm H‘bHaYWFNZ+'& 2!; 2:5: zoloclgfim© w fl ( C a FIW‘W‘ flaw-D § I I : +[§-+(“6-i;m§2_f] (3"‘éJ/a-(T—D I I . I. _-i ‘ l N) (can‘t) . i \ HM ‘7" M5429 '- 1 ' 1 nwd +0 be oweFM chowm mr’riod was mom five nozzle; +hv00fi- \‘+Q;t'cx“i'10 A may Q 0+ come FL 3 - seq. HocHob 0(7an “For 0W WPVDWH 1 i v) Cram mm Ma) can emfly amoeba-{.9 ‘1“(33 Pia) 4mm: 3 I Hem cg: (fixgok a? wok. rem-H‘s" using Thros‘l“ Pd' mum am we}: 3.31067 m 2 3 2 ' e, .1113;a {PEI—‘9 =~ magmas TTI'Z,r VH- 0-5m ‘From +abtsm@ “n.5,? ’51.; me;- 3.7m Pea/9Q," @0052“! 13mm .Ha+lq\o m: Her-0mm; ' . . . Pe/Po= 0,005.2. “Hat-Hob on Page; I %AAE 539: Homework #1, Problem #3 %Jim Sisco % % clear all; close all; %Chamber Properties gam = 1.2; MW = 17.6; %lbm/lbmol Tc = 6400; %R PC = 2250; %psi %Read Excel file and assign variables contour = xlsread('hwklprb3contour.xls', 1, 'A2:B440'); z = contour(:,1); %in r contour(:,2); %in %Find throat radius [rt it] = min(r); %in At = pi*rt“2; %in“2 %Calculate A(z) and e(z) = A(z)/At A = pi*r.“2; %in‘2 AR = A./At; %—— %Newtons method iteration to determine M(z) maxit = 1000; %Maximum number of iterations allowed toler = 0.0001; %Error tolerance for iteration area = length(AR); %Length'of AR vector %Step through 2 for k = lzarea %Setting initial guess if k == Minfg(1) = 0.1; %Initial guess at first axial position elseif k == it+1; Minfg(l) = 1.008; %IG for first position downstream of throat else Minfg(l) = M(k—1); %IG for all positions except above end if k == it M(k) = 1.00; %Set Mach = l at the throat — no iteration else %Iteration for Mach number for i = lzmaxit F(i) = (l/Minfg(i))*((2+(gamr1)*Minfg(i)A2)/(gam+l))“... ‘ ((gam+1)/(2*(gaflrl})) - AR(k); Fp(i) = (—l/Minfg(i)"2)*((2+(gam—l)*Minfg(i)"2)/(gam+l))... A((gam+1)/(2*(gam—l))) + --- ((2+(gamrl)*Minfg(i)“2)/(gam+1))“((3—gam)/(2*(gamF1))}P %Newton's method calculation Minfg(i+1) = Minfg(i) — F(i)/Fp(i); %Error calcuation error(i) = Minfg(i+1) — Minfg(i); %Check for error within tolerance if error(i) <= toler M(k) = Minfg(i); break; end end end end %Calculation of Static Temperature and Pressure T = Tc.*(1 + ((gamrl)/2).*M.“2).‘—1; P = Pc.*(1 + ((gam—l)/2) .*M."2)."—(gam/(gam-1)); %Plot of Nozzle Contour figure(l) plot(z,r); axis([0 4.5 0 4.5]); xlabel('z (in)'); ylabe1('r (in)'); title('AAE 539: Homework #1, Problem 3 — Nozzle Geometry'); grid; %Plot of Mach number vs. 2 figure(2) plot(z,M); xlabel('z (in)'); ylabel('M'); title(‘AAE 539: Homework #1, Problem 3 * Mach Number vs. 2'); grid; %Plot of Static Temperature vs. 2 figure(3) plot(z,T); xlabel('z (in)'); ylabel('T (R)'); title('AAE 539: Homework #1, Problem 3 — Static Temperature vs. 2'); grid: %Plot of Static Pressure vs. 2 figure(4) plot(z,P); xlabel('z (in)'); ylabel('P (pSi)'); tit1e('AAE 539: Homework #1, Problem 3 — Static Pressure vs. 2'); grid; I I I I I I I I I I I I I I I I ,Vrh‘"............ V F I I I l f l I . _ . _ _ _ _ _ _ _ _ _ _ _ _r _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ 1 n . . . . . . . . . . . . . . I W A e , , , A A u u g . A A r u . . . _ . . . . . . _ . . . c u _ . . . _ _ _ _ _ _ . _ . . . . AAE 539: Homework #1, Problem 3 - Nozzle Geometry -._..-.________1________________J Eu . AAE 539: Homework #1, Problem 3 - Mach Number vs. 7. A . A . A A A A A A A A A A L A A A A _ A A _ A A A A A A A A A A A A A A A A A A A A A A A A A A .A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A A n A A A A _ A _ _ _ A _ A A A _ _ A .A _ _ A A A A A A A A A A A A A A A A A A A A A A A A A A A A A 4.5 1.5 0.5 2 6n) T (R) AAE 539: Homework #1, Problem 3 — Static Temperature vs. 2 6500 6000 4000 3000 2500 2500 2000 1500 P (psi) 1000 500- AAE 539: Homework #1, Probiem 3 - Static Pressure vs. 2 A+ evid‘.‘ Pa, =3 “.3050 psi Hf- ?Q =— H7 ps} I "Hui 13 0m ovarexcmdkwy nozaiea wear- sewrod‘x‘bh as“; fiendadl': fl “6‘3! P56?) ino‘OfiQ'? (is: .1: 6H“? P8x)(0;€$?>( lat-.7 ' P359: 3.5% 9:; < pawmosxag} 47 M rflmegmmn melemefi g 6mm: --rnPL= P500118 '7\ = 085 {for eachficxaea E AV = 79 {<me -'- SPM eve-nix, befmn each Shae, is? = 5008 neabvd' Smud'T-v drag age/0+8 r gHomewor‘k filbofi‘é ME 5361 Spt‘lhfl 3007. Solnl " EHomawork=HiCoOfi+j AAE 53:9 ' SPr‘mS 2507 PM (WW 5 33313, SW; (can’t) l—QHJS‘DO-O-gS) ( n6 fink; Sxa‘n mdxoofies mam fiuae.» imam us 0+ wCGQSlble (.9 M'stm' ‘ 780093— . m M. = My 2- 5' == 36106-5.— ML: ISOQ k3 m‘=7\3=0485 ' How-Jr wr’rh Swanax Shae; I 9—”. , In May Teéwl-SW) 9 9,9610% /@OOS°"'5"5“)1 _ Probiexn ‘fi ‘14 (can‘D 'Twa Singfi CWNTD ~ now Oflodcfi'e ’3'} “@851 I HR‘ = MR; 3.76251 we (“El "‘7’" W a |—MR,(&—‘AQ I—(éJaafixi-was) mm: St"? 58513;? l<3 ' mg“ = 0—70”. = (flSJQassw 1:3) RT 0 $5" mo| :1 mm ~l-W\.‘;3 '1' mm = 4' + i molt. lwo Sfalafi, Summary MPLUCS) HOIS - ml!) (kg) 10H8\ [937 rap (#3) 5°Ibct© . $50” 7\ 0.?5 7 . 0.35 NC? 3-3 3-53 mo (t3) 80885 H015 I ‘ wwww “55"? W E apt-‘63" “2°? T chblggm 1%: g. (ml-1+.) - ' \ “PM ' ' M} “AV; :Ava: aeoo% j mPL'a': I506 k3 ‘hltmy =7‘3 I Iqafisy; 915% = 309.3 ' . ' t fSTmrJr \M‘H‘n 5rd fimaef Jaemmfs/(aoosfisfigw )J =7.J.'-ll°13x ! i I i 3 E i i 5 l i g Corfir'mu'ma le-h O‘H‘Qfl' afiaw'. i [3+ SE. 6 2m 5+? 6rd Haze.» mp,_(k3) r5625 “8% 1500 mi,ng 5321 IN? - .501 ' Mpfta) 2mm meg 2840 Mo (ta) 50430 18628 4241 ’7\ . . 0.85 . [6.85 . 0.85 Nessa 3.51 M Hofiework4$l AAE SEQ % ‘SPr‘II‘h-a‘ I ' V? ; W,WW:WMWWMM mwmmmmmmmwm - 3 Probbm “3% Wmn‘i‘) an)i = 5V; =- 5V3 =va = '9503' Nagy-Am, aow‘zs mpLLtz'l-SOO k3 33W I§?&% i???) aux-:13?” -- 55m ma. emf ME; = M129“- 6 Ja+ «Hose. fincikSi-aaé M 31% mm. (ha) {886% “Bi l 1 5488 W1) (t3) F575! 16!?) W1 M? (£23) 31.253 0113‘? 3060 amo 2 mg (kg) H3863 mm 8H1 W68; 7\ o ’85 0525 o . 85 a £35 £95 ’% (“5) I a $12319 SE33» no+ ‘Fmfl’u’ I I TWO- 8+9; 3 . _u. I o-lok home Lea 3~8+a a GM} r“) as a H— :fierscox man wow? redid-1w a hair 0'0 mass wirikea léycpfia c1523: nfiadqmsalose, OD ' " .. 3181531 +§+ha 4L2. iddgfiwogmgm‘k] fine, H+h shah Is nov’r wefl-h Th . Th lgaflormqw. mmafi-eara based m “Huh? ro . +La 8 . fiwmgmaammm fimgm-mgn i i i % i I Av ms L615 1.95 W5 g g i t I ...
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SP07hwk1soln - i Hemmer-1.: 14:1 g ME 5361 ' % gyms mm ; ®...

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