1_8 - PHY 5346 HW Set 2 Solutions Kimel 2. 1.8 We will be...

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Unformatted text preview: PHY 5346 HW Set 2 Solutions Kimel 2. 1.8 We will be using Gauss's law E da a) 1) Parallel plate capacitor Q enc 0 From Gauss's law E W 0 0 Q A 0 0 12 d Q A 0 2 Q Ad A 0 12 d A 0 12 d 2 2 2 2) Spherical capacitor E 2 3 d x 0E 2 Ad 2 Q2 1 d 1 2 0 A 2 0 A d 1 2 0A 2 12 d From Gauss's law, E 12 W 0 b 1 4 0 Q r2 , a r b. a Edr 0 Q 4 0 2 a r 2 dr b b 2 1 Q b a 4 0 ba 0 Q 2 4 0 ba 12 b a 2 1 Q b a 8 0 ba 2 E2d3x 2 Q 4 0 a 4 r rdr 4 4 0 ba 12 b a 2 2 b ba a Q 4 0 4 b a ba 2 12 b a W 1 8 0 3) Cylindrical conductor 2 0 ba From Gauss' s law, E2rL 12 W 0 L 0 Q 0 a Edr b 0 Q 2 0 L Q 2 0 L 2 0 L 12 ln b a a 2 2 b Q dr ln b r a 2 0 L 0 2 E2d3x W 1 4 2 b 2L rdr 1 2 4 a r Q2 ln b a L 0 L ln b a 0L 2 12 ln b a b) w 2 E 1) w r 0 2 0 2 Q A 0 2 2 1 Q 2 0 A2 0 r d, 0 otherwise. 2) w r 0 2 1 4 0 Q r2 2 32 1 0 2 Q2 r4 , a r b, 0, otherwise 3) w r 0 2 Q 2 0 Lr 2 Q2 1 8 0 2L 2r2 , 0 otherwise. ...
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This note was uploaded on 01/10/2012 for the course PHYSIS 506 taught by Professor Smith during the Spring '08 term at University of Arkansas Community College at Morrilton.

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