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# 2_6 - PHY 5346 HW Set 3 Solutions – Kimel 4 2.6 We are...

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Unformatted text preview: PHY 5346 HW Set 3 Solutions – Kimel 4. 2.6 We are considering two conducting spheres of radii r a and r b respectively. The charges on the spheres are Q a and Q b . a) The process is that you start with q a Ý 1 Þ and q b Ý 1 Þ at the centers of the spheres, and sphere a then is an equipotential from charge q a Ý 1 Þ but not from q b Ý 1 Þ and vice versa. To correct this we use the method of images for spheres as discussed in class. This gives the iterative equations given in the text. b) q a Ý 1 Þ and q b Ý 1 Þ are determined from the two requirements > j = 1 K q a Ý j Þ = Q a and > j = 1 K q b Ý j Þ = Q b As a program equation, we use a do-loop of the form > j = 2 n ß q a Ý j Þ = ? r a q b Ý j ? 1 Þ d b Ý j ? 1 Þ à and similar equations for q b Ý j Þ , x a Ý j Þ , x b Ý j Þ , d a Ý j Þ , d b Ý j Þ . The potential outside the spheres is given by d Ý x 3 Þ = 1 4 ^ P > j = 1 n q a Ý j Þ x 3 ? x a Ý j Þ k !...
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2_6 - PHY 5346 HW Set 3 Solutions – Kimel 4 2.6 We are...

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