Section_2.5-2.7_F11

# Section_2.5-2.7_F11 - F = Fx i Fy j Fz k F= 2 Fx Fy 2 Fz 2...

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k F j F i F F z y x + + = 2 2 2 z y x F F F F + + =

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k A A j A A i A A u z y x A + + = k j i u A γ β α cos cos cos + + =
2.6 Vector addition and subtraction : The resultant force is the sum of all the forces: B A F + = B A F - = ( 29 ( 29 k B j B i B k A j A i A z y x z y x + + + + + = ( 29 ( 29 ( 29 k B A j B A i B A z z y y x x + + + + + = ( 29 ( 29 ( 29 k B A j B A i B A z z y y x x - + - + - = + + = k F j F i F F z y x

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AB r B r = A r - A r AB r A x = i A y + j A z + k B r B x = i B y + j B z + k = ( 29 B x A x - i + ( 29 B y A y - j + ( 29 B z A z - k Let’s derive eqn for position vector r AB , with: Position vector r AB is defined by eqn:
Example #1 : A 700 lb force acts on a line from

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Section_2.5-2.7_F11 - F = Fx i Fy j Fz k F= 2 Fx Fy 2 Fz 2...

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