Fall 2011 Exam 2 - Name: CWID #: Section Number: ENSC 2113...

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Unformatted text preview: Name: CWID #: Section Number: ENSC 2113 - FALL 2011 - EXAM #2 EACH PROBLEM IS WORTH 25 POINTS. BOX YOUR ANSWERS AND PROVIDE PROPER UNITS, WHERE APPLICABLE. CALCULATIONS AND FREE BODY DIAGRAMS MUST BE SHOWN THAT SUPPORT THE ANSWER TO RECEIVE CREDIT. 1) Calculate the centroidai iocation of the object below, measured from each axis, using composite bodies. 512:: r EZEZI 190 as ice = MI .42 290W. \‘II-‘VZ flush/149: I‘IIAfla vivid x = 260—- MHZ = 528.929 r__ 2A’2‘C_ 0 q _._ 2555 _ V‘i-Oi‘i‘I‘GI-I'I :il 2 i K= 2A ' wwm’ I" EAT ’ ‘Wimai WA W 2) Determine the force in members GI, GH, and DF and indicate if the member is in tension or compression. List all zero force members. JJ 2Me=o= at)? ('13 —5(e-9) Jr 7.53 ( \(DFD it»: were)! +3 2w: 7.8500) + as?» C41="\5.?:(p C019 tasty r053 3) The member is supported by a journal bearing at A and by cables at B. ‘ Determine the components of reaction atA and B utilizing the right hand ruie. —- . . I @ ZMFO‘; Mm +gTM®> + % Tbb(éj "500 (‘93 @éuvm *émdz) éTwGD fiozflgév‘é‘v 4300(2) fig» : 4r 5:; \F _ O: 4.491%; —t.cpTgp+l(ooO Tm:- “T-m, + 1000 ’EGZNHWNMZ HM: Mo @ 1 3L +7960 3; +950 @Zfim; #6 Tim +5 pr+350 o: gTBD—Cooot‘s'rw _ 290: L2.pr Tabszwzai‘i @2‘r9aw: Ag + éTax) ’f 3T?” 590 Wm @ Tbc, = — 205.33 + \000 @éN%=°= H»; — ETRClechwQ hm: "Him Mi «we: ewe} Fv—DMCQ: ‘ngzTOO M’ml 4) Determine the support reactions at the fixed support A when distance a = 4m. Neglect the thickness of the beam. ¢ éfitofi -\O +u1‘5 '\* M AW: “LES W AX AK: 0 92mm: Mt Jr \D (1.92%) - ii'LUJCQ MAT-rib W'Mb’ ...
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Fall 2011 Exam 2 - Name: CWID #: Section Number: ENSC 2113...

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