quiz8fall00 - EJSC Answer 3313, anv Fall 2000 4 Questions...

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3313, Fall 2000 Quiz 8 Name Answer anv 4 Questions onlv, 1 point each A polypropylene molecule, HO-( -C3B6- )500-OH, was initiated and terminated with free radicals. Of the ~ mass of the molecule, what fraction represents the contribution of the end groups? Total mass = 2(1 + 16) + 500[3 x 12) + (6 x 1)] = 21,034 amu Mass of End Groups = 2(1 + 16) = 34 aInU f .34 aInU 3 ractlon = 21,034 aInU = 1.6 x 10- = 0.16% 2. Calculate the polydispersivity index (PDI) for a polymer given the following data: Molecular Weight Mean Mi Ran2e (J!/mol) (J!/mol) Xi Wi 5,000-10,000 7,500 0.05 0.02 10,000-15,000 12,500 0.16 0.10 15,000-20,000 17,500 0.22 0.18 20,000-25,000 22,500 0.27 0.29 25,000-30,000 27,500 0.20 0.26 30,000-35,000 32,500 0.08 0.13 35,000-40,000 37,500 0.02 0.02 Hence pm = LQ21 -li 3. This is a "Callister" text diagram. Reason what the caption is! You do D.Q! need to have seen this text to answer! You
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This note was uploaded on 01/10/2012 for the course ENSC 3313 taught by Professor Staff during the Fall '11 term at Oklahoma State.

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quiz8fall00 - EJSC Answer 3313, anv Fall 2000 4 Questions...

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