Qz11-F02 - ENSC 3313, Fall ltltll Quiz 11 Name answer any 4...

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Unformatted text preview: ENSC 3313, Fall ltltll Quiz 11 Name answer any 4 gueag'gns only, 1 point each F . 1What have Ihlaoked out on this diagram? Add explanatory comments. RESIQTIVITY ya I‘EMPERATURE PURE the less perfect the lattice, the more Considering electrons as waves, distort the lattice, as does interference to electron motion. hnpuritieg thermal energy that causes vibrations. arumrylai r RECUllfict, P = presidtlfil 4' P‘lhenrlal 2. The sketch purports to illustrate the electron occupancy of the 5 hand of a group I metal at room temperature. It is wrong on '2 accounts. Explain! "‘ The 5 hand holds 2 electronsfatom. Group I metals supply 1, therefore the band should #- ‘oe hall" l'ull. DENSITY DF * The temperature is not absolute zero. so the ENERGY transition occupied to empty should not he STATES abrupt. N (E) 3. At what energy level above the Fermi energy level would the use of the Fermi rather than the Boltzmann distribution law came a 213% difference in the answer? Assume 293 K, RT = 01125 c'y'. 1 l __ = L1: t;—|aT tit 1+er—en-er 1 Let RT = 91325 old [room temperature) Let E — Er - K rifle Then Iii}:— = Hence 5 = c"'fix ,.-. 5:61-64. _ elm: Ki 4. What is Lhe Siupr: urlht: line equal to? ELEUJ‘IUCAL CUNDUCTHFITY OF INTRINSIC SEMI- CONDUCTURS H — n-rfi'r'ilmr'l U " I“! II- “; wussrmr uA-CL- 5"” Elna“ -N|'ll.'l'. “1 I: e 'I'iu' ' s1 H] \\ aims Es ., "a 2k in RH H“ i 5. Estimate the electrical resistivity,r sf III]? at 30°C. Boltzmann’s constant is 3.151 x lll':1 sW’K. flush-u mammal-c:- Utilising Table 11-4.: ww— .E m w fl_fl_m_fisi_if — mm. m mm. mum, p] U; E 3 -J mm It“! I"! 4!. p. M'"I" u. at 1 _ _ a bubstltutlng I I am (LN ~45 n.IT m: {1.0" 0331 _ I3 1 I _.__ m {1.113 M 0.15 0.0415 5 :4 1r M43 5130'}; — exp 5 |: ] mm :41: as a.“ an: a 9.5“ 2(3filx1fll‘ 2'33 303 min” nms I11 an ms 111* m m P2 - Mains - m m 0.25 m m — — 0.613 (II? {1.3-1 1.3 M19 W11 — 0—H! M Dfl Isl E33 MM 10“ m M l}.11 IL? 11.60 m — {LEM 1UP U11 IJ 13.4? 0.015 Sill] ME? sun {was use m m in" M34 m m 0.13 I: um _ m as 039 11 mm m — _ 532E} _ 3:1"; _3 _ .. “'91._. "' ____“'_ ‘ Wflmhlm ii. If thc electrics] mnductifity at" s photocnnductm fslls fig Qfl‘fi. in m l s after the remnst nf The, hght sum-cs, by what prsportinn would it have fallen in l'IZl':I s? i = c "'1 Rspcsting nl'l I x z c IG",.-'lm'“,.":.3} Suhstihmng ll] 1 = 6. mil = s” x =63 x = .TD 1 2104323 1 : .7’9 an no 01' it would haw-c decreased by .21 ...
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This note was uploaded on 01/10/2012 for the course ENSC 3313 taught by Professor Staff during the Fall '11 term at Oklahoma State.

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Qz11-F02 - ENSC 3313, Fall ltltll Quiz 11 Name answer any 4...

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