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p143_26 - Problem 26 Page 143 I suppose you nished part(a...

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Problem 26 Page 143 I suppose you finished part ( a ) and part ( b ). Then from part ( b ), you should get y m y m = 4(6 + β ) 3 27(4 + β ) 2 (1) For part ( c ), we need to determine the smallest value of β for which y m 4, hence y m 4 ⇐⇒ 4(6 + β ) 3 27(4 + β ) 2 4 ⇐⇒ β 6 + 6 3 (2) Hence the smallest value for β is 6 + 6 3. Here is the details: First dividing 4 on both sides and moving 27(4 + β ) 2 on the right hand side: 4(6 + β ) 3 27(4 + β ) 2 4 ⇐⇒ (6 + β ) 3 27(4 + β )
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