Answers to Problems Midterm 2

Answers to Problems Midterm 2 - Answers to Problems from...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Answers to Problems from book 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 100 min 17.1 W 972 kJ 35.5 kΩ a) 28.9 mA b) 3 V a) 832 ms b) 416 ms 4.81 µF a) 40 mA b) 0 mA c) 0 V d) 6.67 mA g) 0 mA h) 6.67 mA i) 66.7 V j) 0 mA 5.69 mA downward a) 1.07 × 105 m/s b) 0 m/s B = -1.04 T in k direction v = -13800 m/s in i direction 1.64 mm 10.2 kN a) ( µ 0 J 0 r2 ) / ( 3 R ) b) (µ0 J0 R2) / (3 r) a) 0.0182 T b) 9.54 × 10-6 T a) 22.6 cm b) 2800 orbits 11.8 mT in -x direction e) 6.67 mA k) 0 mA f) 66.7 V l) 0 V ...
View Full Document

This note was uploaded on 01/10/2012 for the course PHYS 2114 taught by Professor Bandy during the Spring '08 term at Oklahoma State.

Ask a homework question - tutors are online