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HW2B_Sol_3_F11 - ORANGE COUNTRY HOMEWORK SET 2 ORANGE...

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Unformatted text preview: ORANGE COUNTRY HOMEWORK SET 2 ORANGE COUNTRY Phys 21 14 Instructor: Professor Bandy Fall 2011 1. Two IO—cm-diameter charged thin rings face each other, 20 cm apart. The lefi‘ ring is charged to ~20 ”C and the right ring is charged to +2.0 11C. 3. What is the electric field E , both magnitude and direction, at the midpoint between the two rings? b. Calculate the force F on a 1.0 nC charge placed at the midpoint? 2. The electric field strength 5. 0 cm from a very long charged thin wire is 2000 NC. Calculate the electric field strength 10.0 cm from the wire? 3. An electric dipole is formed from two charges, 1' q , spaced 1.0 cm apart. The dipole is at the origin, oriented along the y-axis. The electric field strength at the point (Icy) = (0,10) in cm is 360 MC. 2!. Calculate the dipole moment [3 and charge q. 1). Calculate the electric field strength at the point (x,y) = (10. 0) in cm. 4. The electric flux through the surface shown in Fig. 1 is 15.0 ng/C. Calculate the uniform electric field strength. 5. The electric field strength just above one face of a copper penny is 2000 N/C. Calculate the surface charge density on this face of the penny @ A thin, horizontal 10 cm x 10 cm copper plate is charged withl.0 x lO’Oelectmns. If the electrons are uniformly distributed on the surface, calculate the strength and direction of the electric field: a. 0. 1 mm above the center of the top surface of the plate. b. at the plate’s center of mass. c. 0.1 mm below the center of the bottom surface of the plate. 6‘) The cube in Fig. 2 has edge length of1.4 m and is oriented as shown in a region of uniform electric field. Find the electric flux through the right face if the electric field in N/C is given by a. 6. 0i , b. — 2.0} , and c. —3. 0; +4. 0}; . (1. Calculate the total flux through the cube for each field. 8. Figure 3 show a hollow cavity within a neutral conductor. A point. charge Q is inside the cavity. What is the net electric flux through the closed surface that surrounds the conductor? G) A disk of radius 2.5 cm has a surface charge density of 5. 3 pC/mz on its upper face. Calculate the magnitude of the electric field produced by the disk at a point on its central axis at a distancex = 12 cm from the disk? ® An electron is released from rest in a uniform electric field of magnitude 2.0 x 104 N /C . Calculate the acceleration of the electron. (Ignore gravitation.) " I I I I Closed smface 0cmx10cm Figure 3 Figure l ' Figure 2 Hmafimgt’ 557’ Z ((9) 1;; a?! lo» A J m Wm—fiw. N I ~ - I > LA 10W / W‘IOX/Ola )4 /z£’g'C1Ie(JA}SpU 710,? .10 G? o v I 4.1; .5. ”1’1””..5 up ‘1 > [/1 Zlgowamusmu yawn, mm T3 to), 2 a. Yvodxm m mam/s rad/47‘ J g- A 5:7;13 'w/ 0:; w/ ?:ng A? $ (‘9 S‘XWMMI (ax/0"?) G‘vo-S’xro C l y ‘ . (cm/m)"1 §fla (3“ :r 670 2% m a v“ 80x10” ‘ / ( )El 3 My 3 (’4) A! my ww’zggf 7070 4 /¢ NM «fir ~=~ b -— ( 9 mg,” l ’a E./A}S/D£ A¢o~.au&70£. [.5 A'LW/‘FTS 25430 A A N! . (a) Ea : 7070 (1) /¢ 5:: 4.5. @ NOTE coaeomA—rs bSS/Cufi'floal j»; z. A“ w-m. .5 ‘4 <3. i’fiw 3AA? (m 5 AND clA M5 fifi/EPEN’DICIUM’C “J 8 g N“ WM”. » .a A W /-ml/ '7 %e:}E «M "4»- EA 441495 "fi 0 x” -> ,V 1A («62) E?— 20 (”d) /<./ ,9.) j—E‘v’lf“fi Z'Zo(;j)%'(/HM)1 5}}. -ng W? (L "'- w-‘ w: A Ir" (a) f r: E If; 2:: ('33.ka —r‘-l.aA{¢) 4%. . (bu/'54) 4 -_—_~ 0 CH __._.__ --~ .4 L"="-> k'jta’ va't‘ , z J’ZPU ”av ””10 (/0583ka 15 film/973 ngé: . @225 “:3“ i Ewan.) OHM. >=A,5></03N/ I92 5‘ D/SK m A?) a; L) Vim-m. 4 0‘=‘ 5.5 x 10"" (3%qu 7 F/ ~ if 6215 15m mm” 4": . E; v2.0x1g3LlM/Q' WHAWS' 4' " M “ m 7%”?! ACWAJA’7W7 A3». #6 a 01~)¢Ia If)v :(WX'D: 2. M 5.57 Km ”/5; 9 // Km ”95’ ...
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