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HW2T_Sol_2_F11

# HW2T_Sol_2_F11 - ORANGE COUNTRY HOMEWORK SET 2 ORANGE...

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Unformatted text preview: ORANGE COUNTRY HOMEWORK SET 2 ORANGE COUNTRY Phys 2114 Instmctor'. Professor Bandy Fall 2011 ® Two IO-cm—diameter charged thin rings face each other, 20 cm apart. The left ring is charged to —20 HC and the right ring is charged to +20 nC. a. What is the electric ﬁeld E, both magnitude and direction, at the midpoint between the two rings? b. Calculate the force F on a [.0 11C. charge placed at the midpoint? Q) The electric field strength 5. 0 cm from a very long charged thin Wire is 2000 /C. Calculate the electric ﬁeld strength 10. 0 cm from the wire? ® An electric dipole is formed ﬁom two charges, i q , spaced 1.0 cm apart. The dipole is at the origin, oriented along the y—axis. The electric field strength at the point my) = (0.10) in cm is 3 60 MC. 3. Calculate the dipole moment [3 and charge q. 1). Calculate the electric ﬁeld strength at the point (x,y) = (10, 0) in cm. The electric ﬂux through the surface shown in Fig. 1 is 15.0N .z/C. Calculate the uniform electric ﬁeld strength. 5. The electric ﬁeld strength just above one face of a copper penny is 2000 N/ T Calculate the surface charge density on this face of the penny 6. A thin, horizontal 10 cm x 10 cm copper plate is charged withl.0 x lOloelectrons. If the electrons are uniformly distributed on the surface, calculate the strength and direction of the electric ﬁeld: a. 0. 1 mm above the center of the top surface of the plate. 1). at the plate’s center of mass. c. 0.1 mm below the center of the bottom surface of the plate. 7. The cube in Fig. 2 has edge length of1.4 m and is oriented as shown in a region of uniform electric ﬁeld. Find the electric ﬂux through the right face if the electric ﬁeld in N/C is given by a. 6.0; , b. - 2.0} , and c. -30; + 4.01; . d. Calculate the total ﬂux through the cube for each ﬁeld. 8. Figure 3 show a hollow cavity Within a neutral conductor. A point charge Q is inside the cavity. What is the net electric ﬂux through the closed surface that surrounds the conductor? 9. A disk of radius 2.5 cm has a surface charge density of 5. 3 pC/mz on its upper face. Calculate the magnitude of the electric ﬁeld produced by the disk at a point on its central axis at a distance): = I 2 cm from the disk? 10. An electron is released from rest in a uniform electric ﬁeld of magnitude 2.0 x 104 N / C . Calculate the acceleration of the electron. (Ignore gravitation.) z a I l Closed surface 00mx100m Figure 3 Figure 1 " Figure 2 «Haws/weak. \$872 ’. 2; 3. ‘f /2000 «ﬂout i""‘*‘ @ 4 = 50m (ré/HJHJS) E; <—-——-—«————— zoom—“MW; X = ,0 ' L «A 4 x m‘ J‘ '3 = LEL~ (I: a u AL ,, z: LXI-r +53 3/2. j E 5’9 Fiﬁ/“D 5mm I + E; E 9W x. 5!: x; N57 _ a. 3/ * K 3/2.— KM + 4 ) 7‘ (xﬁ a») a X)» NML 2 ‘1 Eva, “ 7’” ( 0X10 c)(o.1m) 2 (20 \$109.0)(o nu) [(0 ll v14)" + (0.09933 3/1 “”45 (ammm 4L0) (/14) 4- (6,6SM)W] a zooaj /c, E: :2 ’s‘ @3 lac/m. Er 5.1 11\$} "”— 7‘ ‘7’: Y1" S r: f“ E / E I 39,, “T: g, 2' 1° ' try % ‘/ )0 ={q ’1 E1 44(qu {D we. Shaun? 131064 21% I A ' A 4W‘Q P 6W: 5AM; V 3&05 ”/6. @ (“#9)er E a £33 M d - EAg‘fﬁ -n :[email protected],(100»WOM/L "A 'KF 'J A” ‘ p , . ’ EM 5 m3 = “’1 EH Cir/é MIIWMW ,2 - 2m; 212;“— N A /“ '2'"ng /c f) .5; m m z 503'“ = (Mme 40 5: ”\$3.. : ’5' "2% '5‘“ 1752 N'/ _____~c. ...
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