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HW10B_Sol_18_F11

HW10B_Sol_18_F11 - GRANGE CO UNTRV SET 10 OR A NGE COU...

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Unformatted text preview: GRANGE CO UNTRV SET 10 OR A NGE COU N'TRY Phys 2114 instructor: Professor Bandy Fall 2011 1. a. A 111 Hz source of emf has a peak voltage of 50 V. Draw the emf phasor at 3.0 ms. b. Draw the phasor for the emf g : (170 V) cos((_27rx60Hz)t) at t = 60 ms. 2. The peak current through a capacitor is 10.0 mA. What is the current if: a. the emf frequency is doubled? b, the emf peak voltage is doubled (at the original frequency)? c. the frequency is halved and, at the same time, the emfis doubled? @ a. A high~pass RC ﬁlter with a crossover frequency of 1000 Hz uses a 100 Q resistor. Calculate the value of the capacitor. b. A low-pass RC ﬁlter with a crossover frequency of 1000 Hz uses a 100 .Q resistor. Calculate the value of the capacitor. 4. A 500 ,uH inductor is connected across an AC generator that produces a peak voltage of 5.0 V. a. At What frequency f is the peak current 50 mA? I). What is the instantaneous value of the emf at the instant when iL = ‘IL? (Note: lower case i represents instantaneous current) 5. a. What inductor in series with a 100 Qresistor and a 2.5 ,sz capacitor gives a resonance frequency of J 000 Hz? b. What capacitor in series with a 100 1‘2 resistor and a 20 mH inductor gives a resonance frequency of 1000 Hz? A resistor dissipates 2.0 1‘2-‘when the rms voltage of the emf is 10.0 V. At what rms voltage will the resistor dissipate 10. 0 k @ a. What is the peak current supplied by the emf in Fig. 1. b. What is the peak voltage across the 3 #F capacitor? c. Replace each capacitor with a resistor as in Fig. 2 and double 80. What is the average power supplied by the emf and what is the energy dissipated by each resistor? 93 a. A damped LC circuit consists of a 0.15 ,uF capacitor and a 20 W inductor with resistance 1.6 .Q How many cycles will the circuit oscillate before the peak voltage on the capacitor drops to half its initial value? b. A damped RLC circuit includes a 5.0 .Qresistor and a 100 mH inductor. If half the initial energy is lost after 15 cycles, what is the capacitance? Figure 3 shows a rectangular loop of wire immersed in a nonuniform and varying magnetic ﬁeld E? that is perpendicular to and directed into the page. The ﬁeld’s magnitude is given by B : 412x2 , with B in Tesla, tin seconds and x in meters. The loop has width w = 3.0 m and height h = 2.0 m. Calculate the magnitude and direction of the induced emf E around the loop at t y =0.103. 200 L? Figure 1 Figure 2 Figure 3 ) I l/ _ __ {a ‘ a ‘5‘ 1 l\,_’ l {5/ —f7 / I l 3 _ /, u ‘ J . 1/ -l I ’1 . 1/. °- 1 " ._ l .. .- ‘.. -—~ -- . —--— r ’- ( <',. ,v’ - r » ‘ . . w K a.» y‘ I .. 4 . ﬂ: , \ I X _ > ‘ _. _ A _.- . ’ / ff, i (. ’ J’I “EL/[J ( '1; w r\». J 1/ - / ﬂ ‘ /' 7’41. :"'“ ' -.'-’ :LLﬂL—J ILJC : .I’. .r ,ex-A cw 144/ ‘ ' ’ ’ ‘ M r" ‘ ’ / wg—‘J—‘m ’ 7/ ‘, . , ' — , ; . 4 - 7 }.-’ ’ (Hr/.JV/EZ/L/ ,-: 4‘ (1‘ C ‘5 112. L7? 4 t; (“A v.» ‘ / 'L l, l '1 E z lava-V ; .. r "‘5 \ _« _ V. @ R ‘ /F“ “ m” " 5 0'9" ,5 V0515 ‘” Av 2 H (‘~ ,I ~, 1 T ,MV "4 1.— ” , K .1, @ D "i (-1, 1/5 L I ‘ Q ’ , , - VF. c1 —' l 3 ' I Aux- t/\_; 1 7/ .5 1a 2 1' / M’ _ q 1",. "/33 U ‘ / "'1 ‘ I A . 1‘ '“ r '7‘ in? r VTT/Mvvlt’ v r 1/ /-« ‘ I / x O -,. ﬂ Vmca {é- 2“ A r' I "I: ’1 —,- (mfajﬂ . ﬂ 1 \' My“ 6 >" 1450.521 , N wring”; ‘ V w. 334 z H. w \1 ~ : 357.”; 3 as My 55 {7’4 ms Vi“ um; q a an r— , QoV ..L ’ -—" :: We» OWLC, AV. Dov/Take .4 foM 5 ﬂ ,4)? (mm s 0.3“W Plea—c»: K : (O’DS’ M VMGVQ :: :_ <0.aS':4-)('2—<raf¢7 5-" /0»"‘/ .ap mars ragga: V'oh'gug 5:, ﬂaw-35, we 4. 42kg): 1391» J; Kigzsr’oes ’5 ‘20 V — 70V 1” /0 V % Pa 54 E3255 5‘17:.a-‘a--‘??f7 . 1.. ‘P Nf‘a"“‘5 ff €00 3»- “‘ .- . ‘3 \“ <2 .53: ‘3' M?" 51’; W ‘ .. ‘1? ‘xf’v E‘MIL%£LT4 93m}; (w o 63%) GIIk/Cf S‘s" kc (- [1,; J’ / bu} (T ; f “‘1 ‘ ( mi '1 “r’ my EL!9 ._.2 . I (f: [:4 LN!) T'fugyd an .Qdfﬁual I (i n 1,] 13 D .—J 5 '1 (5 ” B'd'és -—— BI 24 .. 1.14.3: lg; I _,E (14.2,, 2. t a ['y37.) N ~15 " ’* * mi” m 54 my ** w 17/ x 4%: #wg‘; 7-- ,] .«I k V a c a M "£0 ‘1‘" gr“, '3 “)3 m W0 t ; .t _ ‘ U w p z _ , a h R - ‘ émﬁf} ‘° d-CEG “mtg?” 3% ., {Pﬁﬁt—ﬁ? AM: QH‘JWDJS E V “NWT-— “1 i‘ m y “at n 1! /" a CW? “3 t i? .uvg n,-_e,.g.g.: AME) Imam» WW»? ‘L ,— 0 , - F. . g TﬁHEQ 4.3;": 'r‘a '_“,,_L.~, 'r ‘ ’ ‘ ' 0‘ Q and. = HHV “MW 0 ' - «we #:2ng Mi L05? 5F"? 3" % 7m» iﬁiLi-M a 1m- W \ BMW D; VT " CA; { IR .9. T {S CLO ’2’"; ‘1’ {gang erAé‘ﬂh-Q; n R. .. 44, am. 00? 9F\$:‘*'=aéE~*-i> 7‘5“ ‘ ...
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