lecture_02_F2011

# lecture_02_F2011 - = = + + + = i i 2 i i i i 3 2 1 r r Q q...

This preview shows pages 1–8. Sign up to view the full content.

Lecture 2 Chapter 20 Page 1 Definition: The electric field at any point is the force per unit charge that would be   experienced by a (very, very small) positive charge at that point:       = = Test q F E Vector = Vector Source = the charge (or distribution) causing the E Field Point = the location of interest. Problem: Given a point charge q = +10 nC . Find the electric field at a distance of 1.0 cm. + - Source Field Point R 1 R 2

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Lecture 2 Chapter 20 Page 2 Problem: Electric field at a position due to one charge Find the electric field a E and b E at locations a and b respectively due to q = +5 nC . See the figure below . Give the electric field in component form where necessary. q Y(cm) X(cm) - 2 2 1 a b 2
Lecture 2 Chapter 20 Page 3 Superposition Principle for Electric Field: = = + + + = i i i i i r r q k E E E E E ˆ ... 2 3 2 1 What if I put a charge Q = q 1 at location P? Now electrical force is calculated or

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: = = + + + = i i 2 i i i i 3 2 1 r r Q q k F F F F F ... P Lecture 2 Chapter 20 Page 4 Problem: Electric field at a position due to three charges sources. Find the electric field at the unoccupied position of the square. Use position 1 as origin. q 1 (-1.0 nC) q 2 ( + 1.0 nC) q 3 ( 1.0 nC) 2.0 cm Lecture 2 Chapter 20 Page 5 CONTINUOUS CHARGE DISTRIBUTION Lecture 2 Chapter 20 Page 6 General: The electric field due to a uniformly charged rod : Lecture 2 Chapter 20 Page 7 Electric Field due to a uniform ring of charge Lecture 2 Chapter 20 Page 8 ProBlem Find the magnitude of the electric field due to a charged ring of radius r = 10 cm and a total charge Q = 6.2 nC , at a point on the ring axis a distance x = 10 cm from the rings center....
View Full Document

## This note was uploaded on 01/10/2012 for the course PHYS 2114 taught by Professor Bandy during the Spring '08 term at Oklahoma State.

### Page1 / 8

lecture_02_F2011 - = = + + + = i i 2 i i i i 3 2 1 r r Q q...

This preview shows document pages 1 - 8. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online