lecture_02_F2011

lecture_02_F2011 - = = + + + = i i 2 i i i i 3 2 1 r r Q q...

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Lecture 2 Chapter 20 Page 1 Definition: The electric field at any point is the force per unit charge that would be   experienced by a (very, very small) positive charge at that point:       = = Test q F E Vector = Vector Source = the charge (or distribution) causing the E Field Point = the location of interest. Problem: Given a point charge q = +10 nC . Find the electric field at a distance of 1.0 cm. + - Source Field Point R 1 R 2
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Lecture 2 Chapter 20 Page 2 Problem: Electric field at a position due to one charge Find the electric field a E and b E at locations a and b respectively due to q = +5 nC . See the figure below . Give the electric field in component form where necessary. q Y(cm) X(cm) - 2 2 1 a b 2
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Lecture 2 Chapter 20 Page 3 Superposition Principle for Electric Field: = = + + + = i i i i i r r q k E E E E E ˆ ... 2 3 2 1 What if I put a charge Q = q 1 at location P? Now electrical force is calculated or
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Unformatted text preview: = = + + + = i i 2 i i i i 3 2 1 r r Q q k F F F F F ... P Lecture 2 Chapter 20 Page 4 Problem: Electric field at a position due to three charges sources. Find the electric field at the unoccupied position of the square. Use position 1 as origin. q 1 (-1.0 nC) q 2 ( + 1.0 nC) q 3 ( 1.0 nC) 2.0 cm Lecture 2 Chapter 20 Page 5 CONTINUOUS CHARGE DISTRIBUTION Lecture 2 Chapter 20 Page 6 General: The electric field due to a uniformly charged rod : Lecture 2 Chapter 20 Page 7 Electric Field due to a uniform ring of charge Lecture 2 Chapter 20 Page 8 ProBlem Find the magnitude of the electric field due to a charged ring of radius r = 10 cm and a total charge Q = 6.2 nC , at a point on the ring axis a distance x = 10 cm from the rings center....
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This note was uploaded on 01/10/2012 for the course PHYS 2114 taught by Professor Bandy during the Spring '08 term at Oklahoma State.

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lecture_02_F2011 - = = + + + = i i 2 i i i i 3 2 1 r r Q q...

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