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lecture_14_F2011

# lecture_14_F2011 - Electrons and protons with the same...

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Lecture 14 Chapter 26 Page 1 Magnetic field due to a current in a long straight wire: Taking Care of business: Biot-Savart Law: - × = 2 o r r L d I 4 B ˆ π μ = π θ θ θ θ π μ 0 2 2 2 o d a a I 4 B csc csc sin = π θ θ π μ 0 o d a I 4 B sin Line of induction

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Lecture 14 Chapter 26 Page 2 Magnetic Force Between two conducting wires with currents: O O O O O O O O O O O O x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x
Lecture 14 Chapter 26 Page 3 Text Problem 26-36 In standard household wiring, parallel wires about 1 cm apart carry currents of about 15 A . What is the magnitude of the force per unit length between such wires?

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Lecture 14 Chapter 26 Page 4 Magnetic Flux: Review of two of Maxwell’s Equations:
Lecture 14 Chapter 26 Page 5 Text Problem 26 – 28 What is the magnitude of the force on a 50-cm -long wire carrying a 15.0 A at right angles to a

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Unformatted text preview: Electrons and protons with the same kinetic energy are moving at right angles to a uniform magnetic field. How do their orbital radii compare? Lecture 14 Chapter 26 Page 6 Text Problem 26 – 45 A particle carrying a 50-C charge moves with velocity k i v ˆ 2 . 3 ˆ . 5 + = m/s through a uniform magnetic field j i B ˆ 7 . 6 ˆ 4 . 9 + = T. a. Find the magnetic force m F on the particle. b. Form the dot products v F ⋅ and B F ⋅ to show explicitly that the force is perpendicular to both v and B . Text Problem 26 – 45 continued b. Form the dot products v F ⋅ and B F ⋅ to show explicitly that the force is perpendicular to both v and B ....
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