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Exam 3 - PHYS 1214 THIRD HOUR EXAM “coal Laboratory...

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Unformatted text preview: PHYS 1214 THIRD HOUR EXAM “coal Laboratory Section Number SO THAT YOU HAVE ONE EMPTY SEAT ON our calculator, two pencils, and the am are blank. to provide scratch (10 points each) and EITHER SIDE! SIT IN A SEAT This is a closed book exam. You should have only y exam paper at your seat. The last two pages of the ex paper. The test consists of 7 multiple—choice questions/problems two problems to be solved (40 points each). USEFUL FORMULAS AND CONSTANTS (Vectors are indicated with arrows) At 2Trr y S a r _ 1 8 V é— B E v XszL c=——’——e3x10 m/s I=»—- \IEO'IJO ' XC AQ V V 2 LAT 1:}; 1:; wo=~36 50:835X10_12N0m2 2 _ . u N A c—f 7» F=I-L-B-srn(q>) L: 06 §=N-B-A-w-sin(wt) F=qvV-B-SIn(¢) cos( —R V3 NS 1p 1 (p)__——— -—-—:———:—-— XC:———- Z Vp Np IS 000 __. _31 2 _ me 9.11x10 kg ZztIR +(XL—XC)2 p0 =4nx1o 7T.m/A n I : I " V a Slnea Nb Slneb nair _ 1-00 “water = 1.33 I : —“— XL 1 1_1 R °S_,+g'—'f’ EZC'B V29 f: —— Sinecrltzflb- n 2 na PART ONE: MULTIPLE-CHOICE (10 POINTS EACH) 6 1. Light with frequency 5.80 x 1014 Hz travels in water which has an index of R refraction of 1.33. The wavelength of this light in water is ». (d)"3.89 x 10‘7 m (a) 6.79 x 10'7 m (b) 9.62 x 10'8 m (c) 7.45 x 10-7 m (e) 5.61 x 10'7 m )1 g ‘ 2:26 QMOQ. 2:». :z x (o I“ 2. Which one of the following is m; an electromagnetic wave? (a) ultraviolet light, (b), sound waves (c) visible light (d) microwaves (e) Gamma—rays 3. The angular frequency at which a 10.0 mH inductor has the same reactance as a 5.00 uF capacitor is ,4470 rad/s (b) 850 rad/s (c) 1930 rad/s (d) 225 rad/s 7860 rad/s (A) = 2......» O «075 , l » W (to #63) (5 mm) 4. As you move an object from just outside to just inside the focal point of a diverging lens, its image (a) goes from real to virtual and from inverted to erect K (b) goes from inverted to erect, but remains real (0) goes from inverted to erect, but remains virtual. (d) goes from real to virtual, but remains inverted. sane“ dew—5 MW . “A (e) remains both erect and virtual.\> «ME-W...W......-”M.wummmmwwwwm»flwaflme Base your answers to 5 and 6 on the figure below Water n2=1 .33 5. A light ray going from glass to water makes an angle 6=42° with the normal to the glass-water interface. The refracted angle in the water is (a) 23‘» (b) 36° (c) 71° (e) 88° l\§O(Sin 92°) 2 l.%3 smeb gm f #12; was 6. The value that 9 must equal in order to be the critical angle is (a) 31.8° (c) 51.7° (d) 25.6° (e) 75.4° \33 7. Circle the statements below that are true concerning possible images from a concave mirror (there may be more than one): .al, on the same side of the object, smaller in size than the object virtual, behind the mirror, less than the size of the object irtual, on the same side as the object, larger in size than the object (d) real, behind the mirror, larger in size than the object _% (9) virtual, behind the mirror, larger in size than the object ‘ PART TWO: PROBLEMS (40 POINTS EACH) 27ng/é/{1/“J Work out the following two problems. Put boxes around all an ers/ make sure they are clearly labeled. Be sure to show all work clearly. Answers with no clear reasoning will receive little or no credit. 1. A voltage source with a 30.0 V amplitude and an angular frequency of 250 rad/s is connected in a series circuit which includes a 2000 resistor and a ' 0.40 H inductor. A) Determine the impedance of the series circuit. B) Determine the current amplitude in the series circuit. C) Determine the voltage amplitudes across the resistor and across the inductor. D) Determine the phase angle Cl) of the source voltage with respect to the current and state whether it lags or leads the current. E) Construct the phasor diagram} A] gem; Wat/€42) 03'1":- {gm Vz‘lK V: I XL V”; QERXQOOJQ V: (5mm (swam/SEC . W) V‘V’Tesifitm" v: » inductor m Cos d» E.- z ._ QOGJL CABS (b ' 35335.4, ¢=oos“‘(. 2W) PART TWO: PROBLEMS (40 POINTS EACH) { d 2. A) B) For the two lenses below, the arrows represent real objects. Use ligh construct the images. State whether the images are: (i) real or virtual (ii) erect or inverted Using the values for the focal length and object distance, calculate the image distance and magnification for each case. Converging lens, f=14 cm, s=18 cm ...
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