Solutions_Assignment 3 Fall 11

Solutions_Assignment 3 Fall 11 - 3. a Student 1 2 3 4 5 6 7...

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3. a Student Test A Test B d 1 78 82 -4 16 2 86 74 12 144 3 74 79 -5 25 4 72 93 -21 441 5 75 80 -5 25 6 68 82 -14 196 7 77 99 -22 484 Σd = -59 Σd² = 1330 We do not reject and conclude that there is no difference in the mean scores of test A and test B. b. MINITAB Solution: Paired T-Test and CI: Test A, Test B Paired T for Test A - Test B N Mean StDev SE Mean Test A 7 75.71 5.62 2.12 Test B 7 84.14 8.71 3.29 Difference 7 -8.43 11.79 4.46 95% CI for mean difference: (-19.33, 2.47) T-Test of mean difference = 0 (vs not = 0): T-Value = -1.89 P-Value = 0.107
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P-value = 0.107 is greater than α =0.05 can not reject 4. Since Do not reject , TV ad campaign did not help or hurt the sales. 5. Do not reject. The students who take the XYZ prep do not meet the
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This note was uploaded on 01/11/2012 for the course STATS 1305 taught by Professor Shahmai during the Spring '11 term at NYU.

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Solutions_Assignment 3 Fall 11 - 3. a Student 1 2 3 4 5 6 7...

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