Sec 2.1-Focus

Sec 2.1-Focus - m – 5 6 = 9 6 h k 9 12 = 3 12 i y 2 = 8 j...

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Solving Linear Equations, Part 1 page 2.1 - 21 Section 2.1 Focus Exercises 1. Determine if the replacement value shown (after each equation) is a solution of that equation. a) 3p – 2 = 6; p = 3 b) 9 – 3k = 7k – 11; k = 2 c) 5m + (4 – m) = 3(m – 2) 2; m = - 4 d) 1 6 x 1 3 x = x – 6 3 ; x = 12 2. Solve each equation by isolating the variable. SHOW ALL STEPS! a) p + 2 = 4 b) x 8 = 9 c) y 9 = - 6 d) b + 1 = - 5 e) r 4 = - 4 f) w + 3 = 3 g)

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Unformatted text preview: m – 5 6 = 9 6 h) k + 9 12 = 3 12 i) y + 2 = - 8 j) c – 1 = - 6 Solving Linear Equations, Part 1 page 2.1 - 22 3. Solve each equation by isolating the variable. SHOW ALL STEPS! a) 7x = 56 b) 9m = - 63 c)- 6x = 24 d)- 12p = - 36 e) 10x = 15 f) 5m = - 9 g) 7 3 x = 28 h) 3 2 y = - 30 i) 4 7 n = - 2 j) 5 8 v = 15 4 k) y 9 = 2 l) 7n 8 = - 1 m)- 6m = 4 n)- 8x = - 18 o)-6 7 x = - 12 p)-5 4 k = 15 2...
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Sec 2.1-Focus - m – 5 6 = 9 6 h k 9 12 = 3 12 i y 2 = 8 j...

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