Chapter 7 solutions

Chapter 7 solutions - 1.14 72-1-3 7'53 T'JfiE 7.69 7'34...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 1.14 72-1-3 7'53 T'JfiE 7.69 7'34 7-32 1.5”] {a} point : {b1 poinrd {: It will increase { It will decrease I'EE = 1:1111." = £2.04 x 10‘ kg}, at: k—m H" I 1 I a hr, @6005, .. 11cm ,- I "1 ={:'>.IZI4 x 1|1‘5 kng.-'sl)|ii .1tutni kgmlsr, = 594 x 1011:] _ . I ._ -' z a .=.=L:J=[1_tIx1tI* gH101-1.134+|[99 "c —15- “c1 1“ - 5 t. .1th01. =31|11t1 33:5 1:4.1341 g'L'IL'" x 100 g x 1.5m: =1.2:'.><1tl’1 b)1.2li><1IZI'.T £11.25 x 1041: (1.353134 "C" x1120 —25.5|:|:|‘=C><K E 3:34.? g 4.131g" "cr' xii-hi x 10‘ g}>c-:2.".31— 25.2431 = 2.1x1ti‘ J: 111:] Keep- id mind Heat the total Luass must be censttieredin this :alcuiattma: and that birth liquids: once mixed. merge the same temperamre m:rease: 11eaT= (4.12 .T-‘g T} x {55.0 g +510 :1 35-1313 “C — 13.5 “CJ = 3.3 x1011 of heat emery released Next determine the Ember cufmeles clf reactant irtrculted Lu the reaciiclu: (1.0550 L x 1.3 mcIJ-CL =CI.IZI TE 1391 of acid and cufhase. " I 115.1 I" U 1,3.Ex10111W1 Thus the enrhaJpv clause is: L=4= :33 U ' ' Luel [DDT-'2 LuelJ £01 {a} Divide the given equaden 111' 4. Ni-L-“gj — .'-.-4 0:131 —_} 5101(3) + Bil-LOG) 5H” = —1132 15154 = 433 B1 {1:1 Divide the given equaden 111' 5 2.-'3N'H. j+ Fifi 0:131 —,>2.-'3 Nil-I131 + I-LDEg} eI-P = —1132 k1-‘Ii = 435? 1:1 Reverse the first equaiicln. muliiph' the Jesuit bvm'ru: and add it to the second equation; 2K1: 1(5) + Hip-:4") —t 2HC1figj + Ill-[011(5): - =‘ = 4411.1 HI H-_.SO.(:I:3) - HIGH-:5) —> REE-[:3 - $53!}. =‘ = —341.4 kl Adding gives 1.15: 21-0.“. 1(5) + H-_-SD.(I!'J —} EHClrgjl + K3504fi51. -_‘LH=‘ = 54.3 H LnJJHEllE'J «JEN Id'Ll Mqutply the second equation by m1:- ami add 111m tngethet: stag-3:) — Jim-:33 —} 31g:N-.-(:}+ 3mg} dH“ =—3 ?1 HI Nuts) + 3H-.-II32I —* Him-Lei - ° =2t—4fi m stag-:5) — 1:91;. —> Mgfifisj dH“ =45] e1 m2 grim..ch = '27 ems-ragga) + wrap-:63} — damn} = 1; GEE-93.5ij - 29255.? El) —{—25§|D.3 B1) = +1163 k1 ...
View Full Document

This note was uploaded on 01/12/2012 for the course CHEM 103 taught by Professor Jeffashley during the Fall '10 term at Philadelphia.

Page1 / 2

Chapter 7 solutions - 1.14 72-1-3 7'53 T'JfiE 7.69 7'34...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online