Unformatted text preview: (Note that if we could not get the 1 by switching the rows we would just multiply Row 1 times 1/3.) Step 2 We want a 0 below the first 1. We will use the 3 rd elementary row operation and multiply Row 1 times –3 and add the result to Row 2. Be careful that you only change the row you are adding to . Step 3 We want our 1 in the second column. We will use the second elementary row operation and multiply Row 2 times 1/7. Note that the resulting 1 is called a “pivot”. Step 4 The only remaining step is to get a 0 above our pivot in the second column. To accomplish this we will again use the third elementary row operation and add 1 times Row 2 to Row 1. Solution: _______________________ (Make sure your solution is written as an ordered pair since it is a point.)...
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 Spring '08
 DUCK
 Systems Of Equations, Equations, Multiplication, GaussJordan Elimination, Linear Systems, Row, Elementary matrix

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