SurCalCh2Sec4 - times the derivative of the numerator FIRST...

This preview shows pages 1–2. Sign up to view the full content.

2.4—The Product and Quotient Rules TV, S01 Product Rule [ ] ) ( ' ) ( ) ( ' ) ( ) ( ) ( x f x g x g x f x g x f dx d + = In other words, the derivative of a product of two functions is the first function times the derivative of the second function plus the second function times the derivative of the first. Note: For the product rule it doesn’t matter which part you put first since there is a +sign between. #12 #18 Quotient Rule [ ] 2 ) ( ) ( ' ) ( ) ( ' ) ( ) ( ) ( x g x g x f x f x g x g x f dx d = The derivative of a quotient is the denominator times the derivative of the numerator minus the numerator times the derivative of the denominator, all divided by the square of the denominator. ( lolo hidlo lodhi ) Note: For the quotient rule it makes a big difference which part you do first. You must do the denominator

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: times the derivative of the numerator FIRST or you will get the wrong answer since there is a minus sign between terms. #28 #32 DEFINITION Average Cost per unit= x x C x AC ) ( ) ( = . Similar definitions apply for Average Revenue and Average Profit. Marginal average cost is the rate at which average cost is changing, = x x C dx d x MAC ) ( ) ( Marginal Average Revenue is the rate at which Average Revenue is changing, = x x R dx d x MAR ) ( ) ( Marginal Average Profit is the rate at which Average Profit is changing, = x x P dx d x MAP ) ( ) ( #48 #50...
View Full Document

{[ snackBarMessage ]}

What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern