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Unformatted text preview: 16 1 2 1 dx x How can we extend this to evaluate 1 2 1 dx x ? You guessed it! We will take the limit as the upper limit of integration approaches infinity. That is, = b b dx x dx x 1 2 1 2 1 lim 1 . Evaluate: 1 2 1 dx x Now evaluate 1 1 dx x What makes the difference in the value of the integral? Now evaluate + dx e e x x 2 1 The second type of improper integral is the type where there is a point of discontinuity in the interval [a,b]. The discontinuity could occur at either an endpoint or at a point inside the interval. Example: e dx x 2 ln Now evaluate 1 1 2 1 dx x...
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This note was uploaded on 01/13/2012 for the course MATH 2564 taught by Professor Pamelasatterfield during the Spring '12 term at NorthWest Arkansas Community College.
 Spring '12
 PamelaSatterfield
 Improper Integrals, Integrals

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