exam3 - ECE~255 _ Exam 111 APRIL/7/2010 Name: (Please print...

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Unformatted text preview: ECE~255 _ Exam 111 APRIL/7/2010 Name: (Please print clearly) Student ID: INSTRUCTIONS This is a closed book, closed notes exam. Carefully mark your multiple choice answers on the scantron form. Work on multiple choice problems and marked answers in the, test booklet will not be‘graded. Nothing is to be on the seat beside you. When the exam ends, all writing is to stop. This is not negotiable. No writing while turning in the exam/scantron or risk an F in the exam. All students are expected to abide by the customary ethical standards of the university, i.e., your answers must reflect only your own knowledge and reasoning ability. As a reminder, at the very minimum, cheating will result in a zero on the exam and possibly an F in the course. Communicating with any of your classmates, in any language, by any means, for any reason, at any time between the official start of the exam and the official end of the exam is grounds for immediate ejection from the exam site and loss of all credit for this exercise. NOTE: Choose the answer that is closest to what youhave calculated; many answers are rounded to the first non-decimal point ECE—ZSS, Ex 3 Sp 2010 page 2 1) What is the value Of output impedance (R0) for the current mirror shown below? Assume B=oo, VBE(ON)=0.7V, VA=100V 5V lflkfl (1) co (2) 232M! (3) 107m (4) 0 (5) 116k§2 '(6) None of the above I ECE-ZSS, Ex 3 Sp 2010 page 3 2) For the Widlar current source shown below, what value of R issrequired to set 10:25 FLA, “Lei-“510011.131 and AE2/AEI=5 Assume VT=25mV , VBE(ON)=0.7V and ignore base Widthrmodulation (1) 3kg (2) 30m (3) 3009 (4) 150:2 (5) 150m (6) None of the above ‘1 ’ In K: {(102 1452) EOE-255, Ex 3 Sp 2010 page '4 3) Figure below is internal structure of an OpAmp, what is the current 1324? Assume Q4 arld Q? are identical, B=100, and VBE(ON)=O.7V (the circuit is symmetric and since Q4 and Q5 are 1dentlcal ICQEICQs) WHSV __ .7 ~-R,=-2okn _ j ___ 7 a muzokn I mam _m 2.31: Q: ' QI 92 + VM '9. ‘ _IiBfi m '90 a a} 4x R5=1537 m ' ; 1135:3207 ,‘7-15,VKEM,,=i, (1) lmA (2) 2mA (3) 0.25mA ' (4) SmA (5) OmA (6) None of the above T l5- .— o 9 “We? 3 _‘_" o-g’ rm} EOE-255, Ex 3 Sp 2010 page S , 4) What is the configuratioh of the multistage amplifier shown below? (1) CC-CB-CE (2) CC-CE—CC (3) CE-CE-CC T (4) CB—CE-CE (5) CB-CE-CC (6) None of the above CE.» (’55:; (‘C ECE-255, Ex 3 Sp 2010 page 6 5). What are the input impedance of the amplifier shown below, if gm=20mS, [3:75, if0=100kQ, R1=S 009, RB: 15kg, RE=3009, and RL=12kQ. VT=25mV ' : - (1') Rin=15kQ (2) Rm=3k£2 (3) Rin=2909 (4) Rin=100k£2 - (5) Rm=10ko (6) None of the above R'ALZg “[Vf,~f 2.. II,” H [3.31; + 23”»3'007 M 2,2. “5" 'C M 2.6.1?le Bea-255, Ex 3 Sp 2010 page 7 _ 6)_ What is the value of the input impedance for theamplifier shown below, if Ie=12-5H~A, 3:100, VA=60Vs u r R1409, R4=100k£2, and RL=100k.Q. VT=25mV . ' (1) Rm=100ko (2} Rin=2k9 (3) Rin=200k§2 (4) Rin=50kfl (5) Rin=500§2 (6) None ‘of the above [-1 ace-255, Ex 3 Sp 2010 page a 7) What is the absolute value of the voltage gain (lvo/vif) for the amplifier Whose ac equivalent circuit is shown below? Assume the MOSFET Q points are (2111A, 7.5V), Kn=1mAfV2, and i=0 (1) 16 (2)8 (3)540 (4) 25 (5) gain is zero since we ignored the channel lengthmodulation (6) None of the above Gitk: j’kflL j“. 7’" ZI<IO '1: leofl'g 14); "azuran 3.4 Ic—‘L ‘ gn- TW-*~J in .—. 16: . I 1442.! 2 7-7»-6'?_'(- ‘A N :1; .. 4,8 ' _-' Mel/M ECE-ZSS, Ex 3 Sp 2010 page 9 8) For the two stage amplifier shown below, what is the absolute value of the voltage gain Av=|volvi|? Assume for the MOSFET VTN=1V, KN='0.2mA/v2, xeo and for the BJT, [3:80, and VA=1 00v. VT=25mV 4000 (2) 1 (3) 200 (4) 154 (S) 80 ‘ (6) None of the above _. I: 0.; VJIn ICJL 3““ = --—-:?F'3_& ’53-":550 l I AV 1: EXIou-s X [5.61:1] Zak] Z ‘ EDI-’1'” 5"”? jade/u! ECE—ZSS, Ex 3 Sp 2010 page 10 '9) What is the absolute value of the voltage gain (lvo/viD of the'following amplifier biased with a current source, Assume B=100, and VA=80V for all transistors. VBE(ON)=0.7V (1) 1-600 _ (2) 160 (3) 1 ' (4) 3200 ' (5) 300 ’ - _(6) None of the above 2—3 3"" 7.. «ii—p. ; Ll 2‘0“; .4. 2;" u ’2 L “LIL-o. .. €60 'I EOE-255,131: 3 Sp 2010 page 11 10) What is the absolute value of the voltage gain of the ampiifier' shown below .(IV0/Vigl), Assume g,n:5mAN " I. and 1‘0 is large. ' (2) 10 (3) 1 (4) 14 (5) 7 . 7-11.);25, (IQ-None of the above ' ‘ 3m“; : sx1."3.[5'”'2] “’7 ...
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This note was uploaded on 01/12/2012 for the course ECE 255 taught by Professor Staff during the Fall '08 term at Purdue.

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exam3 - ECE~255 _ Exam 111 APRIL/7/2010 Name: (Please print...

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