# HW9 - 15.40 (a) b ( 29 I C = α F I E = 100 101 100 μ A (...

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Unformatted text preview: 15.40 (a) b ( 29 I C = α F I E = 100 101 100 μ A ( 29 = 99.0 μ A V CE = 20- 10 5 I C- - 0.7 ( 29 = 10.8 V Q- Po int = 99.0 μ A , 10.8 V ( 29 for both transistors | r π = 100 0.025 V ( 29 99.0 μ A = 25.3 k Ω A cc = - β o R L ' r π + β o + 1 ( 29 R EE = - 100 k Ω 25.3 k Ω + 101 600 k Ω ( 29 = - 0.165 A dd = - β o R L r π + β o + 1 ( 29 R 5 | R L = 100 k Ω 500 k Ω = 83.3 k Ω | R 5 = 600 k Ω 2.5 k Ω = 2.49 k Ω A dd = - 100 83.3 k Ω ( 29 25.3 k Ω + 101 2.49 k Ω ( 29 = - 30.1 | R id = 2 r π + β o + 1 ( 29 R 5 [ ] = 2 25.3 k Ω + 101 2.49 k Ω ( 29 [ ] = 554 k Ω Note : Single - ended CMRR = 0.5 30.1 0.165 = 91.2 and R ic = 0.5 r π + β o + 1 ( 29 R 5 [ ] = 0.5 25.3 k Ω + 101 600 k Ω ( 29 [ ] = 30.3 M Ω 15.50 R EE 100 k Ω Q 1 600 k Ω +- v ic Common-mode half circuit dc half-circuit 100 k Ω +V CC-V EE Q 1 I EE 100 μ A Differential-mode half circuit Q 1 2.5 k Ω +- v id 2 R EE 600 k Ω 100 k Ω 500 k Ω a ( 29 For V O = 0, I C 3 = 15 V 50 k Ω = 300 μ A | V C 2 = 15- 2400 I E 3- V EB 3 = 15- 0.729- 0.7 = 13.6 V I C 1 = I C 2 = α F 200 μ A 2...
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## This note was uploaded on 01/12/2012 for the course ECE 255 taught by Professor Staff during the Fall '08 term at Purdue.

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HW9 - 15.40 (a) b ( 29 I C = α F I E = 100 101 100 μ A (...

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