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# sat - CMSC 451 SAT Coloring Hamiltonian Cycle TSP Slides By...

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Unformatted text preview: CMSC 451: SAT, Coloring, Hamiltonian Cycle, TSP Slides By: Carl Kingsford Department of Computer Science University of Maryland, College Park Based on Sects. 8.2, 8.7, 8.5 of Algorithm Design by Kleinberg & Tardos. Boolean Formulas Boolean Formulas: Variables: x 1 , x 2 , x 3 (can be either true or false ) Terms: t 1 , t 2 , . . . , t ‘ : t j is either x i or ¯ x i (meaning either x i or not x i ). Clauses: t 1 ∨ t 2 ∨ ··· ∨ t ‘ ( ∨ stands for “OR”) A clause is true if any term in it is true . Example 1: ( x 1 ∨ ¯ x 2 ) , ( ¯ x 1 ∨ ¯ x 3 ) , ( x 2 ∨ ¯ v 3 ) Example 2: ( x 1 ∨ x 2 ∨ ¯ x 3 ) , ( ¯ x 2 ∨ x 1 ) Boolean Formulas Def. A truth assignment is a choice of true or false for each variable, ie, a function v : X → { true , false } . Def. A CNF formula is a conjunction of clauses: C 1 ∧ C 2 , ∧··· ∧ C k Example: ( x 1 ∨ ¯ x 2 ) ∧ ( ¯ x 1 ∨ ¯ x 3 ) ∧ ( x 2 ∨ ¯ v 3 ) Def. A truth assignment is a satisfying assignment for such a formula if it makes every clause true . SAT and 3-SAT Satisfiability (SAT) Given a set of clauses C 1 , . . . , C k over variables X = { x 1 , . . . , x n } is there a satisfying assignment? Satisfiability (3-SAT) Given a set of clauses C 1 , . . . , C k , each of length 3 , over variables X = { x 1 , . . . , x n } is there a satisfying assignment? Cook-Levin Theorem Theorem (Cook-Levin) 3-SAT is NP-complete. Proven in early 1970s by Cook. Slightly different proof by Levin independently. Idea of the proof: encode the workings of a Nondeterministic Turing machine for an instance I of problem X ∈ NP as a SAT formula so that the formula is satisfiable if and only if the nondeterministic Turing machine would accept instance I . We won’t have time to prove this, but it gives us our first hard problem. Reducing 3-SAT to Independent Set Thm. 3-SAT ≤ P Independent Set Proof. Suppose we have an algorithm to solve Independent Set, how can we use it to solve 3-SAT? To solve 3-SAT: • you have to choose a term from each clause to set to true , • but you can’t set both x i and ¯ x i to true . How do we do the reduction? 3-SAT ≤ P Independent Set x 1 x 3 x 2 x 2 x 4 x 3 x 1 x 4 x 2 (x 1 ∨ x 2 ∨ x 3 ) ∧ (x 2 ∨ x 3 ∨ x 4 ) ∧ (x 1 ∨ x 2 ∨ x 4 ) Proof Theorem This graph has an independent set of size k iff the formula is satisfiable. Proof. = ⇒ If the formula is satisfiable, there is at least one true literal in each clause. Let S be a set of one such true literal from each clause. | S | = k and no two nodes in S are connected by an edge....
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sat - CMSC 451 SAT Coloring Hamiltonian Cycle TSP Slides By...

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