ch 6 notes

# ch 6 notes - 6.1...

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6.1 Equilibrium -(F(net))(x)=sigma(x)(F(i))(x)=0 -(F(net))(y)=sigma(y)(F(i))(y)=0 -the equilibrium condition of Equations 6.1 applies only to particles, which cannot rotate. -equilibrium of an extended object, which can rotate, requires an additional condition 6.2 Using Newton's Second Law -the essence of Newtonian mechanics can be expressed in two steps: 1. forces on an object determine its acceleration a=F(net)/m 2. object's trajectory can be determined by using a in the equations of kinematics -(F(net))(x)=sigma(F(x))=m*a(x) -(F(net))(y)=sigma(F(y))=m*a(y) 6.3 Mass, Weight, and Gravity -mass is an intrinsic property of an object -a pan balance would give the same result on another planet because it does not depend on the strength of gravity -gravity is an attractive, long-range force between any two objects -Newton's law of gravity: F(1 on 2)=F(2 on 1)=Gm(1)m(2)/r^2 -G=6.67*10^-11 Nm^2/kg^2, called the gravitational constant -F(g)=F(planet on m)=(GMm/R^2, straight down) -For motions whose vertical and horizontal extents are less than roughly 10 km, we can approximate the earth as a flat surface that pulls on objects with a gravitational force

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ch 6 notes - 6.1...

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