Thermodynamics HW Solutions 14

Thermodynamics HW Solutions 14 - Chapter 1 Basics of Heat...

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Chapter 1 Basics of Heat Transfer 1-34 A hot copper block is dropped into water in an insulated tank. The final equilibrium temperature of the tank is to be determined. Assumptions 1 Both the water and the copper block are incompressible substances with constant specific heats at room temperature. 2 The system is stationary and thus the kinetic and potential energy changes are zero, ΔΔ KE PE == 0 and E U = . 3 The system is well-insulated and thus there is no heat transfer. Properties The specific heats of water and the copper block at room temperature are C p, water = 4.18 kJ/kg· ° C and C p, Cu = 0.386 kJ/kg· ° C (Tables A-3 and A-9). Analysis We observe that the volume of a rigid tank is constant We take the entire contents of the tank, water + copper block, as the system . This is a closed system since no mass crosses the system boundary during the process. The energy balance on the system can be expressed as EE E U in out −= = Net energy transfer by heat, work, and mass system Change in internal, kinetic, potential, etc. energies
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