Thermodynamics HW Solutions 63

Thermodynamics HW Solutions 63 -...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Chapter 1 Basics of Heat Transfer 1-123 "GIVEN" L=4 "[m]" D=0.2 "[m]" P_air_in=100 "[kPa]" T_air_in=65 "[C]" "Vel=3 [m/s], parameter to be varied" T_air_out=60 "[C]" eta_furnace=0.82 Cost_gas=0.58 "[$/therm]" "PROPERTIES" R=0.287 "[kJ/kg-K], gas constant of air" C_p=CP(air, T=25) "at room temperature" "ANALYSIS" rho=P_air_in/(R*(T_air_in+273)) A_c=pi*D^2/4 m_dot=rho*A_c*Vel
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Q_dot_loss=m_dot*C_p*(T_air_in-T_air_out)*Convert(kJ/s, kJ/h) Cost_HeatLoss=Q_dot_loss/eta_furnace*Cost_gas*Convert(kJ, therm)*Convert($, cents) Vel [m/s] Cost HeatLoss [Cents/h] 1 0.3934 2 0.7868 3 1.18 4 1.574 5 1.967 6 2.361 7 2.754 8 3.147 9 3.541 10 3.934 1 2 3 4 5 6 7 8 9 10 0.5 1 1.5 2 2.5 3 3.5 4 Vel [m/s] Cost HeatLoss [cents/h] 1-63...
View Full Document

This note was uploaded on 01/14/2012 for the course PHY 4803 taught by Professor Dr.danielarenas during the Fall '10 term at UNF.

Ask a homework question - tutors are online