Thermodynamics HW Solutions 81

Thermodynamics HW Solutions 81 - 2 ] 0.02 521370 0.04...

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Chapter 2 Heat Conduction Equation 2-15E "GIVEN" E_dot=1000 "[W]" L=15 "[in]" "D=0.08 [in], parameter to be varied" "ANALYSIS" g_dot=E_dot/V_wire*Convert(W, Btu/h) V_wire=pi*D^2/4*L*Convert(in^3, ft^3) q_dot=E_dot/A_wire*Convert(W, Btu/h) A_wire=pi*D*L*Convert(in^2, ft^2) D [in] q [Btu/h.ft
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Unformatted text preview: 2 ] 0.02 521370 0.04 260685 0.06 173790 0.08 130342 0.1 104274 0.12 86895 0.14 74481 0.16 65171 0.18 57930 0.2 52137 0.02 0.04 0.06 0.08 0.1 0.12 0.14 0.16 0.18 0.2 50000 100000 150000 200000 250000 300000 350000 400000 450000 500000 550000 D [in] q [Btu/h-ft 2 ] 2-4...
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This note was uploaded on 01/14/2012 for the course PHY 4803 taught by Professor Dr.danielarenas during the Fall '10 term at UNF.

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