Chapter 2 Heat Conduction Equation2-46E A 1.5-kW resistance heater wire is used for space heating. Assuming constant thermal conductivity and one-dimensional heat transfer, the mathematical formulation (the differential equation and the boundary conditions) of this heat conduction problem is to be obtained for steady operation. Assumptions 1Heat transfer is given to be steady and one-dimensional. 2 Thermal conductivity is given to be constant. 3 Heat is generated uniformly in the wire. Analysis The heat flux at the surface of the wire is &&&(.qQAGrLss====s2Win)(15 in).2 W / in2120020062120ππNoting that there is thermal symmetry about the center line and there is uniform heat flux at the outer surface, the differential equation and the boundary conditions for this heat conduction problem can be expressed as 01=+⎟⎠⎞⎜⎝⎛kgdrdTrdrdr&2 kW L= 15 inD= 0.12 indTdrkdT rdrqs()&002120=−==.2 W / in22-47Heat conduction through the bottom section of an aluminum pan that is used to cook stew on top of
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