Thermodynamics HW Solutions 116

Thermodynamics HW Solutions 116 - r [m] T [C] 0.4 100...

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Chapter 2 Heat Conduction Equation 2-71 "GIVEN" r_1=0.40 "[m]" r_2=0.41 "[m]" k=1.5 "[W/m-C]" T_1=100 "[C]" Q_dot=500 "[W]" f_loss=0.10 "ANALYSIS" q_dot_s=((1-f_loss)*Q_dot)/A A=4*pi*r_2^2 T=T_1+(1/r_1-1/r)*(q_dot_s*r_2^2)/k "Variation of temperature" "r is the parameter to be varied"
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Unformatted text preview: r [m] T [C] 0.4 100 0.4011 100.2 0.4022 100.3 0.4033 100.5 0.4044 100.7 0.4056 100.8 0.4067 101 0.4078 101.1 0.4089 101.3 0.41 101.5 0.4 0.402 0.404 0.406 0.408 0.41 100 100.2 100.4 100.6 100.8 101 101.2 101.4 101.6 r [m] T [C] 2-39...
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This note was uploaded on 01/14/2012 for the course PHY 4803 taught by Professor Dr.danielarenas during the Fall '10 term at UNF.

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