Thermodynamics HW Solutions 202

Thermodynamics HW Solutions 202 - r_3=r_2+t_ins*Convert(cm,...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Chapter 15 Steady Heat Conduction 3-69 "GIVEN" T_infinity_1=320 "[C]" T_infinity_2=5 "[C]" k_steel=15 "[W/m-C]" D_i=0.05 "[m]" D_o=0.055 "[m]" r_1=D_i/2 r_2=D_o/2 "t_ins=3 [cm], parameter to be varied" k_ins=0.038 "[W/m-C]" h_o=15 "[W/m^2-C]" h_i=80 "[W/m^2-C]" L=1 "[m]" "ANALYSIS" A_i=pi*D_i*L A_o=pi*(D_o+2*t_ins*Convert(cm, m))*L R_conv_i=1/(h_i*A_i) R_pipe=ln(r_2/r_1)/(2*pi*k_steel*L) R_ins=ln(r_3/r_2)/(2*pi*k_ins*L)
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: r_3=r_2+t_ins*Convert(cm, m) "t_ins is in cm" R_conv_o=1/(h_o*A_o) R_total=R_conv_i+R_pipe+R_ins+R_conv_o Q_dot=(T_infinity_1-T_infinity_2)/R_total DELTAT_pipe=Q_dot*R_pipe DELTAT_ins=Q_dot*R_ins T ins [cm] Q [W] T ins [C] 1 189.5 246.1 2 121.5 278.1 3 93.91 290.1 4 78.78 296.3 5 69.13 300 6 62.38 302.4 7 57.37 304.1 8 53.49 305.4 9 50.37 306.4 10 47.81 307.2 3-45...
View Full Document

Ask a homework question - tutors are online