Thermodynamics HW Solutions 223

Thermodynamics HW Solutions 223 -...

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Chapter 15 Steady Heat Conduction 3-92 "GIVEN" D_1=0.005 "[m]" "t_ins=1 [mm], parameter to be varied" k_ins=0.13 "[W/m-C]" T_ball=50 "[C]" T_infinity=15 "[C]" h_o=20 "[W/m^2-C]" "ANALYSIS" D_2=D_1+2*t_ins*Convert(mm, m) A_o=pi*D_2^2 R_conv_o=1/(h_o*A_o) R_ins=(r_2-r_1)/(4*pi*r_1*r_2*k_ins) r_1=D_1/2 r_2=D_2/2 R_total=R_conv_o+R_ins
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Unformatted text preview: Q_dot=(T_ball-T_infinity)/R_total t ins [mm] Q [W] 0.5 0.07248 1.526 0.1035 2.553 0.1252 3.579 0.139 4.605 0.1474 5.632 0.1523 6.658 0.1552 7.684 0.1569 8.711 0.1577 9.737 0.1581 10.76 0.1581 11.79 0.158 12.82 0.1578 13.84 0.1574 14.87 0.1571 15.89 0.1567 16.92 0.1563 17.95 0.1559 18.97 0.1556 20 0.1552 3-66...
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This note was uploaded on 01/14/2012 for the course PHY 4803 taught by Professor Dr.danielarenas during the Fall '10 term at UNF.

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