MPA 9

# MPA 9 - MasteringPhysics Assignment Print View...

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Assignment 9 - Week 10 Due: 11:53pm on Sunday, November 20, 2011 Note: To understand how points are awarded, read your instructor's Grading Policy . [ Switch to Standard Assignment View] Conceptual Question 21.6 In music, two notes are said to be an octave apart when one note is exactly twice the frequency of the other. Suppose you have a guitar string playing frequency . Part A To increase the frequency by 3 octave(s), to , by what factor would you have to increase the tension? ANSWER: = 64 Correct Part B To increase the frequency by 3 octave(s), to , by what factor would you have to decrease the length? ANSWER: = 8 Correct Open Organ Pipe Conceptual Question An open organ pipe (i.e., a pipe open at both ends) of length has a fundamental frequency . Part A If the organ pipe is cut in half, what is the new fundamental frequency? Hint A.1 Fundamental wavelength in an open pipe Hint not displayed Hint A.2 Fundamental frequency Hint not displayed MasteringPhysics: Assignment Print View http://session.masteringphysics.com/myct/assignmentPrintVi. .. 1 of 6 11/24/11 11:33 AM

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ANSWER: Correct Part B After being cut in half in Part A, the organ pipe is closed off at one end. What is the new fundamental frequency? Hint B.1 Fundamental wavelength in a closed pipe Hint not displayed ANSWER: Correct The fundamental frequency of a half-length closed pipe is equal to that of a full-length open pipe. Part C The air from the pipe in Part B (i.e., the original pipe after being cut in half and closed off at one end) is replaced with helium. (The speed of sound in helium is about three times faster than in air.). What is the approximate new fundamental frequency?
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## This note was uploaded on 01/15/2012 for the course PHYS 101 taught by Professor Bates during the Winter '08 term at UBC.

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MPA 9 - MasteringPhysics Assignment Print View...

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