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lecture20-sound-

# lecture20-sound- - What you can do so far WAVES Iden6fy the...

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What you can do so far … WAVES Iden6fy the components of the wave equa6on What you will be able to do a?er today … how our ears work how sound intensity varies according to distance from the source Explain … sound levels Calculate … mathema6cal manipula6ons of log Apply …

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Phase of a traveling wave M0 (, ) s i n ( ) Dxt D kx t ωφ =
\ \-/ Qt ]uu\L 4' t Lxr'rt'+ 'l'r" pkug cL,Qone"cø ^\ = c!,-4, þ -yr-* L' + ù" \ r.- '9,.- = (Vxr-"¡t + Ð ,) - (t i,-,¡ t + 4,) = LLxz -,ÉL fi" -tzt, +yL;z/Q" t^¡ ^t Lu¡, - k-t, lo- (x r-x ,) ptrir diftw^q. aMLl @r"rls o.. ,\ ""*J x (no r¡- ,),"/n^,U;* !) tubsÀ þ l-< t- rL l4': lll ^ , Zll r., ,. \ A¿)= ;l\t-rt¡) - | /\ Phase diference deriva6on:

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A wave of wavelength λ passes through a string. The phase difference between two points on the string that are a distance λ /4 apart is: A. 0 radians B. π /4 radians C. π /2 radians D. 3 π /4 radians E. π radians
Phase difference between two point on a wave of wavelength λ is π /3 radians. What is the (minimum) separation between these two points in units of wavelength? A. 0 B. λ /6 C. λ /3 D. 2 λ /3 E. λ /12

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A harmonic wave is traveling on a string with a speed of 0.45 m/s. The displacement of a portion of the string at x = 0.012 m is observed to vary with time according to the equation D (0.012, t ) = (0.06 m) sin(1.4 ! 3.5 t ) (a) What is the frequency of the wave?
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lecture20-sound- - What you can do so far WAVES Iden6fy the...

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