Ps2X2soln - PHYSICS DEPARTMENT PHY 2054 Name (print, last...

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PHYSICS DEPARTMENT PHY 2054 2nd Exam (SF 18–21) 11 July 2006 Name (print, last frst): SOLUTIONS Signature: On my honor, I have neither given nor received unauthorized aid on this examination. YOUR TEST NUMBER IS THE 5-DIGIT NUMBER AT THE TOP OF EACH PAGE. (1) Code your test number on your answer sheet (use 76–80 ±or the 5-digit number). Code your name on your answer sheet. DARKEN CIRCLES COMPLETELY. Code your UFID number on your answer sheet. 1 (2) Print your name on this sheet and sign it also. 2 (3) Do all scratch work anywhere on this exam that you like. Circle your answers on the test ±orm. At the end o± the test, this exam printout is to be turned in. No credit will be given without both answer sheet and printout. (4) Blacken the circle o± your intended answer completely, using a #2 pencil or blue or black ink. Do not make any stray marks or some answers may be counted as incorrect. (5) The answers are rounded o f . Choose the closest to exact. There is no penalty ±or guessing. I± you believe that no correct answer is listed, leave this item blank!! (6) Hand in the answer sheet separately. Use±ul (??) Constants: µ 0 = 4π × 10 7 Tm/A 0 = 8 . 85 × 10 12 C 2 /(Nm 2) electron charge = 1 . 6 × 10 19C electron mass = 9 . 11 × 10 31 kg V=volt N=newton J=joule m=meter W=watt µ = “micro-” = 10 6 A = ampere “pico” = 10 12 n = “nano” = 10 9 m = “milli” = 10 3 proton mass = 1 . 67 × 10 27 kg c = 3 × 108 m/s Answer (1) is the correct answer. The (brief) solution is in bold italics like this. [NOTE: ‘RHR’ = “Right Hand Rule”] 1 . Immediately a±ter switch S in the circuit shown is closed, the current through the battery shown is: At t=0 , L acts like an open circuit (due to the initial back emf) so initial current flows only through R1 and R2 (1) Vo/ ( R 1 + R 2) (2) Vo/R 1 (3) Vo/R 2 (4) 0 2. In the diagrams, all light bulbs are identical and all em± devices are identical. In which circuit (I, II, III, IV, V) will the bulbs be dimmest? (1) IV (2) I (3) II (4) III (IV) has 2 bulbs in series across a single emf source, hence the lowest current => dimmest bulbs.
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3. In the circuit shown, the capacitor is initially uncharged and V = 9.0 volts. At time t = 0, switch S is closed. If τ denotes the time constant, the approximate current through the 3Ω resistor when t = τ/ 100 is: (1)1A (2)1/2A (3)3/4A (4)3/8A (5)3/2A i= V/R e -t/τ but t/τ = (τ/100)/ τ = 1/100 so I = V/R e -100
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This note was uploaded on 01/15/2012 for the course PHY 2054 taught by Professor Avery during the Spring '08 term at University of Florida.

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Ps2X2soln - PHYSICS DEPARTMENT PHY 2054 Name (print, last...

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