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Unformatted text preview: Bd = 5.6 x106 T, coming out of the paper. The net field at A is therefore the difference between the two, B = 2.8 x106 T, coming out of the paper . At the other point B = (0.4m, 0.2m), the field due to wire C is coming out but smaller than the field due to wire D, which is pointed in to the paper (the numbers are otherwise the same). The net field at B is therefore B = 2.8 x106 T , going in to the paper. 2. A straight wire in a magnetic field experiences a force of 0.03N when the current in the wire is 2.7A. What is the current in the wire when it experiences a force of .047N? since F = IBl, F 1 /F 2 = I 1 /I 2 . Thus I 2 = I 1 × F 2 / F 1 = 2.7 .047/.03 = 4.23 A C D...
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This note was uploaded on 01/15/2012 for the course PHY 2054 taught by Professor Avery during the Spring '08 term at University of Florida.
 Spring '08
 Avery
 Physics

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