qz1sol_3081sp10 - 8 cm 3000 m = 3000 m (100 cm)/(1 m) = 3...

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TA: Tomoyuki Nakayama Monday, January 11 th , 2010 PHY 2048: Physic 1, Discussion Section 3081 Quiz 1 (Homework Set #1) Name: UFID: Formula sheets are not allowed. Calculators are allowed. Do not store equations in your calculator. You need to show all of your work for full credit. ________________________________________________________________________________ Antarctica is roughly semicircular with a radius of 2000 km. The average thickness of its ice cover is 3000 m. a) How many cubic centimeters of ice does Antarctica contain? We first express the radius and thickness in meters: 2000 km = 2000 km × (1000×100 cm)/(1 km) = 2 × 10
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Unformatted text preview: 8 cm 3000 m = 3000 m (100 cm)/(1 m) = 3 10 5 cm The volume of the half cylinder is given by the area of semicircle times height. Thus we get V = (r 2 /2) h = [3.14 (2 10 8 )2/2] 3 10 5 = 1.88 10 22 cm 3 b) How many cubic feet of ice does Antarctica contain? (1 ft = 30.48 cm) We already have the volume in cm 3 , so all we have to do is to convert it to ft 3 . Since the original unit has cm in numerator, we multiply the conversion factor which has cm in the denominator so that they cancel. We multiply the factor three times. We have V = 1.88 10 22 cm 3 (1 ft/30.48 cm) 3 = 6.64 10 17 ft 3...
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