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qz1sol_3705sp10

# qz1sol_3705sp10 - desired units To remove km we multiply a...

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TA: Tomoyuki Nakayama Monday, January 11 th , 2010 PHY 2048: Physic 1, Discussion Section 3705 Quiz 1 (Homework Set #1) Name: UFID: Formula sheets are not allowed. Calculators are allowed. Do not store equations in your calculator. You need to show all of your work for full credit. ________________________________________________________________________________ An astronomical unit (AU) is the average distance between Earth and the Sun, approximately 1.50 × 10 8 km. a) The average distance between Earth and the moon is approximately 3.84 × 10 5 km. Express the Earth-moon distance in astronomical units. To convert units, we need to multiply conversion factors which remove original units and give
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Unformatted text preview: desired units. To remove km, we multiply a conversion factor which has km in the denominator. We have 3.84 × 10 5 km = 3.84 × 10 5 km × (1 AU/1.50 × 10 8 km) = 2.56 × 10-3 AU b) The speed of light is about 3.0 × 10 8 m/s. Express the speed of light in astronomical units per minute. 1 km = 1000 m, thus 1 AU = 1.5 × 10 11 m. We multiply two conversion factors, one of which converts m to AU, and the other of which converts s to min. 3.0 × 10 8 m/s = 3.0 × 10 8 m/s × (1 AU/1.50 × 10 11 m) × (60 s/1 min) = 1.20 × 10-1 AU/min...
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