qz2sol_3695sp10 - t = 3.00 s? A projectile does not...

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TA: Tomoyuki Nakayama Tuesday, January 26 th , 2010 PHY 2048: Physic 1, Discussion Section 3695 Quiz 2 (Homework Set #3) Name: UFID: Formula sheets are not allowed. Calculators are allowed. Do not store equations in your calculator. You need to show all of your work for full credit. ________________________________________________________________________________ A stone is catapulted at time t = 0, with an initial velocity of magnitude 25.0 m/s and at an angle of 60.0º above the horizontal. a) What are the horizontal and vertical components of the initial velocity? A component of a vector along an axis is the projection of the vector onto that axis. Therefore, v 0x = v 0 cosθ = 25 × cos60º = 12.5 m/s v 0y = v 0 sinθ = 25 × sin60º = 21.7 m/s b) What are the horizontal and vertical component of its velocity at
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Unformatted text preview: t = 3.00 s? A projectile does not accelerate in the horizontal direction. Thus the x-component of its velocity does not change. v x = v 0x = 12.5 m/s A projectile accelerates at a constant rate in the vertical direction. Thus, the y-component of its velocity changes linearly with time. v y = v 0y-gt = 21.7 - 9.8 × 3 = -7.70 m/s c) What are the horizontal and vertical components of its displacement from the catapult site at t = 3.00 s? The horizontal component of a projectile’s velocity is constant, thus the displacement is given by velocity times time interval. Δx = v 0x t = 12.5 × 3 = 37.5 m The vertical component of the displacement is given by a quadratic function of time. Δy = v 0y t - (1/2)gt 2 = 21.7 × 3 - 0.5 × 9.8 × 32 = 21.0 m...
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This note was uploaded on 01/15/2012 for the course PHY 2048 taught by Professor Field during the Fall '08 term at University of Florida.

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