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Unformatted text preview: t = 3.00 s? A projectile does not accelerate in the horizontal direction. Thus the xcomponent of its velocity does not change. v x = v 0x = 12.5 m/s A projectile accelerates at a constant rate in the vertical direction. Thus, the ycomponent of its velocity changes linearly with time. v y = v 0ygt = 21.7  9.8 × 3 = 7.70 m/s c) What are the horizontal and vertical components of its displacement from the catapult site at t = 3.00 s? The horizontal component of a projectile’s velocity is constant, thus the displacement is given by velocity times time interval. Δx = v 0x t = 12.5 × 3 = 37.5 m The vertical component of the displacement is given by a quadratic function of time. Δy = v 0y t  (1/2)gt 2 = 21.7 × 3  0.5 × 9.8 × 32 = 21.0 m...
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This note was uploaded on 01/15/2012 for the course PHY 2048 taught by Professor Field during the Fall '08 term at University of Florida.
 Fall '08
 Field
 Physics, Work

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