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Unformatted text preview: force is W s = 9 J when the displacement is d = 2 m. The definition of work gives W s = Fd F = Ws/d = 4.50 N b) If the can was initially at rest and had a mass of 0.500 kg, what is its speed at the end of the 2.00 m? We apply the workkinetic energy theorem to the can at x = 0 m and x = 2 m, express the kinetic energy in terms of mass and velocity, and solve the equation for the velocity. K = (1/2mv f 2 ) 0 = Ws v = (2Ws/m) = 6.00 m/s c) If the can had an initial kinetic energy of 5.00 J, moving in the positive direction of the x axis, what is its kinetic energy at the end of the 2.00 m? Now the initial kinetic energy is not zero. The workkinetic energy theorem yields K = K f K i = W s K f = K i + W s = 14.0 J...
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 Fall '08
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 Physics, Work

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